Description
Now, here is a fuction:
F(x) = 6 * x^7+8*x^6+7*x^3+5*x^2-y*x (0 <= x <=100)
Can you find the minimum value when x is between 0 and 100.
Input
The first line of the input contains an integer T(1<=T<=100) which means the number of test cases. Then T lines follow, each line has only one real numbers Y.(0 < Y <1e10)
Output
Just the minimum value (accurate up to 4 decimal places),when x is between 0 and 100.
Sample Input
2 100 200
Sample Output
-74.4291 -178.8534
#include<iostream> #include <iomanip> using namespace std; long double fun(double x) { return 42*x*x*x*x*x*x+48*x*x*x*x*x+21*x*x+10*x ; } long double fun1(double x,double y) { return 6*x*x*x*x*x*x*x+8*x*x*x*x*x*x+7*x*x*x+5*x*x - y*x ; } int main() { int t; long double y,hight=100,low=0,mid,k; cin >> t ; while(t--) { cin >> y; hight=100; low=0; while(hight - low >1e-8) { mid=(hight + low)/2; k=fun(mid); if(k>y) { hight=mid; } if(k<y) { low=mid; } } cout << setiosflags(ios::fixed) ; cout << setprecision(4) << fun1(mid , y) << endl; } return 0; }
时间: 2024-10-10 06:58:13