#include <iostream> #include <algorithm> #include <cstdio> #include <math.h> #include <set> #include <map> #include <queue> #include <string> #include <string.h> #include <bitset> #define REP(i,a,n) for(int i=a;i<=n;++i) #define PER(i,a,n) for(int i=n;i>=a;--i) #define hr putchar(10) #define pb push_back #define lc (o<<1) #define rc (lc|1) #define mid ((l+r)>>1) #define ls lc,l,mid #define rs rc,mid+1,r #define x first #define y second #define io std::ios::sync_with_stdio(false) #define endl ‘\n‘ using namespace std; typedef long long ll; typedef pair<int,int> pii; const int P = 1e9+7, INF = 0x3f3f3f3f; ll gcd(ll a,ll b) {return b?gcd(b,a%b):a;} ll qpow(ll a,ll n) {ll r=1%P;for (a%=P;n;a=a*a%P,n>>=1)if(n&1)r=r*a%P;return r;} ll inv(ll x){return x<=1?1:inv(P%x)*(P-P/x)%P;} //head const int N = 2e5+10; int n, q, pos; int a[N], w[N]; ll s1[N<<2], s2[N<<2], sum, tot; void pu(int o) { s1[o]=s1[lc]+s1[rc]; s2[o]=(s2[lc]+s2[rc])%P; } void update(int o, int l, int r, int x, int v) { if (l==r) { s1[o] = v; s2[o] = (ll)v*a[l]%P; return; } if (mid>=x) update(ls,x,v); else update(rs,x,v); pu(o); } ll qry1(int o, int l, int r, int ql, int qr) { if (ql<=l&&r<=qr) return s1[o]; ll ans = 0; if (mid>=ql) ans+=qry1(ls,ql,qr); if (mid<qr) ans+=qry1(rs,ql,qr); return ans; } int qry2(int o, int l, int r, int ql, int qr) { if (ql<=l&&r<=qr) return s2[o]; ll ans = 0; if (mid>=qr) return qry2(ls,ql,qr); if (mid<ql) return qry2(rs,ql,qr); return (qry2(ls,ql,qr)+qry2(rs,ql,qr))%P; } void find(int o, int l, int r, int ql, int qr) { if (sum<=0) return; if (ql<=l&&r<=qr) { if (l==r) { sum -= s1[o]; pos = r; return; } if (sum>s1[lc]) sum-=s1[lc],find(rs,ql,qr); else find(ls,ql,qr); return; } if (mid>=ql) find(ls,ql,qr); if (mid<qr) find(rs,ql,qr); } void build(int o, int l, int r) { if (l==r) { s1[o]=w[l],s2[o]=(ll)a[l]*w[l]%P; return; } build(ls),build(rs); pu(o); } int qry(int l, int r) { int t = qry2(1,1,n,l,r)-qry1(1,1,n,l,r)%P*a[pos]%P; if (t<0) t += P; return t; } signed main() { scanf("%d%d", &n, &q); REP(i,1,n) scanf("%d", a+i),a[i]-=i; REP(i,1,n) scanf("%d", w+i); build(1,1,n); REP(i,1,q) { int x, y; scanf("%d%d", &x, &y); if (x<0) update(1,1,n,-x,y); else { sum = (1+qry1(1,1,n,x,y))/2, pos = 0; find(1,1,n,x,y); int ans = qry(pos,y)-qry(x,pos); if (ans<0) ans+=P; printf("%d\n",ans); } } }
原文地址:https://www.cnblogs.com/uid001/p/10754367.html
时间: 2024-10-16 03:44:57