第一种:
Dao层的方法
Public User selectUser(String name,String password);
对应的Mapper.xm
<select id="selectUser" resultMap="BaseResultMap"> select * from user_user_t where user_name = #{0} and user_password=#{1} </select>
第二种:
该方法采用Map传多参数
Dao层的方法
Public User selectUser(Map paramMap);
对应的Mapper.xml
<select id=" selectUser" resultMap="BaseResultMap"> select * from user_user_t where user_name = #{userName,jdbcType=VARCHAR} and user_password=#{userPassword,jdbcType=VARCHAR} </select>
Service层调用
public User xxxSelectUser(){ Map paramMap=new hashMap(); paramMap.put(“userName”,”对应具体的参数值”); paramMap.put(“userPassword”,”对应具体的参数值”); User user=xxx. selectUser(paramMap);}
个人认为此方法不够直观,见到接口方法不能直接的知道要传的参数是什么。
第三种:
Dao层的方法
Public User selectUser(@param(“userName”)Stringname,@param(“userpassword”)String password);
对应的Mapper.xml
<select id=" selectUser" resultMap="BaseResultMap"> select * from user_user_t where user_name = #{userName,jdbcType=VARCHAR} and user_password=#{userPassword,jdbcType=VARCHAR} </select>
第四种:
mapper.Java:
public List<User> getUserByParam(User use);
对应Mapper.xml:
<select id="getUserByParam" resultType="com.ray.bean.User" parameterType="com.ray.bean.User" > select * from t_pub_user t <where> <if test="{user_name}!=null"> t.user_name like CONCAT(‘%‘,#{user_name},‘%‘) </if> <if test="{user_password}!=null"> and t.user_password like CONCAT(‘%‘,#{user_password},‘%‘) </if> </where> limit #{1},#{2} </select>
时间: 2024-10-22 09:21:13