Problem Description
You just need to calculate the sum of the formula: 1^2+3^2+5^2+……+ n ^2.
Input
In each case, there is an odd positive integer n.
Output
Print the sum. Make sure the sum will not exceed 2^31-1
Sample Input
3
Sample Output
10
用普通的做法会超时,只能用公式算n*(4*n*n-1)/3(其中n为第几个数),还有题目明明说好结果在int范围内的,但是必须用__int64才能过,郁闷。。。
1 #include <stdio.h> 2 3 int main(){ 4 __int64 number; 5 __int64 n; 6 __int64 result; 7 8 while(scanf("%I64d",&number)!=EOF){ 9 n=(number+1)/2; 10 11 result=n*(4*n*n-1)/3; 12 printf("%I64d\n",result); 13 14 } 15 return 0; 16 }
时间: 2024-10-13 16:00:03