string s = " test "; size_t n = s.find_last_not_of(" \r\n\t"); if (n != string::npos){ s.erase(n + 1, s.size() - n); } n = s.find_first_not_of(" \r\n\t"); if (n != string::npos){ s.erase(0, n); }
原文地址:https://www.cnblogs.com/haiyang21/p/9588238.html
时间: 2024-10-21 11:29:55