原理:
找出文件前3个字符
如果它们对应的ASCII 值分别是 239,187,191
则判断为bom头,去掉前3个字符.
代码实现如下:
$basedir = isset($_GET[‘dir‘]) ? $_GET[‘dir‘] : "."; $auto = 1; $auto = isset($_GET[‘auto‘]) ? $_GET[‘auto‘] : $auto; checkdir($basedir); function checkdir($basedir) { if ($dh = opendir($basedir)) { while (($file = readdir($dh)) !== false) { if ($file != ‘.‘ && $file != ‘..‘) { if (!is_dir($basedir . "/" . $file)) { echo "filename: $basedir/$file " . checkBOM("$basedir/$file") . " <br>"; } else { $dirname = $basedir . "/" . $file; checkdir($dirname); } } } closedir($dh); } } function checkBOM($filename) { global $auto; $contents = file_get_contents($filename); $charset[1] = substr($contents, 0, 1); $charset[2] = substr($contents, 1, 1); $charset[3] = substr($contents, 2, 1); if (ord($charset[1]) == 239 && ord($charset[2]) == 187 && ord($charset[3]) == 191) { if ($auto == 1) { $rest = substr($contents, 3); rewrite($filename, $rest); return ("<font color=‘red‘>BOM found, automatically removed.</font>"); } else { return ("<font color=‘red‘>BOM found.</font>"); } } else return ("BOM Not Found."); } function rewrite($filename, $data) { $filenum = fopen($filename, "w"); flock($filenum, LOCK_EX); fwrite($filenum, $data); fclose($filenum); }
时间: 2024-11-04 22:25:21