C语言找出大于一个数的最小回文数的代码

下面代码内容是关于C语言找出大于一个数的最小回文数的代码，希望能对码农们有用途。

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

void main(){
char data[10] = {0}, res[10] = {0}, state[10] = {0}, len = 0, pos, bit = 0;
scanf("%s",data);

len = strlen(data);
    pos = len/2 - 1;
}
else{
    pos = len/2;
}

while(pos - bit >= 0){
    if(len % 2 == 1){
        if(data[pos - bit] >= data[pos + bit]){
            res[pos - bit] = data[pos - bit];
            res[pos + bit] = data[pos - bit];
        }
        else{
            data[pos - bit + 1]++;
            memset(&data[pos - bit + 2], ‘0‘, len - (pos - bit+1));
            bit = 0;
            continue;
        }
        bit ++;
    }
    else{
        if(data[pos - bit] >= data[pos + 1 + bit]){
            res[pos - bit] = data[pos - bit];
            res[pos + 1 + bit] = data[pos - bit];
        }
        else{
            data[pos - bit ]++;
            memset(&data[pos - bit + 1], ‘0‘, len - (pos - bit+1) + 1);
            bit = 0;
            continue;
        }
        bit ++;
    }

}

printf("回文数为%s", res);

}

原文地址：https://blog.51cto.com/14122754/2386672