网络编程- 解决黏包现象方案二之struct模块（七）

server端

import jsonimport structimport socket

sk = socket.socket()sk.bind((‘127.0.0.1‘,8080))sk.listen()

conn,addr = sk.accept()dic_len = conn.recv(4)  # 4个字节 数字的大小dic_len = struct.unpack(‘i‘,dic_len)[0]content = conn.recv(dic_len).decode(‘utf-8‘)  # 70content_dic = json.loads(content)if content_dic[‘operate‘] == ‘upload‘:    with open(content_dic[‘filename‘],‘wb‘) as f:        while content_dic[‘filesize‘]:            file = conn.recv(1024)            f.write(file)            content_dic[‘filesize‘] -= len(file)conn.close()sk.close()

client端

import osimport jsonimport structimport socket

sk = socket.socket()sk.connect((‘127.0.0.1‘,8080))

def get_filename(file_path):    filename = os.path.basename(file_path)    return filename

#选择 操作operate = [‘upload‘,‘download‘]for num,opt in enumerate(operate,1):    print(num,opt)num = int(input(‘请输入您要做的操作序号 : ‘))if num == 1:    ‘‘‘上传操作‘‘‘    file_path = input(‘请输入要上传的文件路径 : ‘)    file_size = os.path.getsize(file_path)  # 获取文件大小    file_name = get_filename(file_path)    dic = {‘operate‘: ‘upload‘, ‘filename‘: file_name,‘filesize‘:file_size}    str_dic = json.dumps(dic).encode(‘utf-8‘)    ret = struct.pack(‘i‘, len(str_dic))  # 将字典的大小转换成一个定长(4)的bytes    sk.send(ret + str_dic)    with open(file_path,‘rb‘) as  f:        while file_size:            content = f.read(1024)            sk.send(content)            file_size -= len(content)elif num == 2:    ‘‘‘下载操作‘‘‘sk.close()

原文地址：https://www.cnblogs.com/mys6/p/10797863.html