多重背包--java

多重背包

有N种物品和一个容量为V的背包。第i种物品最多有n[i]件可用，每件费用是c[i]，价值 是w[i]。求解将哪些物品装入背包可使这些物品的费用总和不超过背包容量，且价值总和最大
母函数的思想也是如此 给你 价值, 物品数量的限制, 然后凑,

hdu2191

import java.util.*;

public class Main {

    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        while (sc.hasNext()) {

            int n = sc.nextInt();
            int m = sc.nextInt();

            int v[] = new int[101];
            int w[] = new int[101];
            int num[] = new int[101];
            for (int i = 0; i < m; i++) {
                v[i] = sc.nextInt();
                w[i] = sc.nextInt();
                num[i] = sc.nextInt();
            }

            int dp[] = new int[10001];
            for (int i = 0; i <= m; i++)
                dp[i] = 0;
            for (int i = 0; i < m; i++) {
                for (int k = 0; k <= num[i]; k++) {
                    for (int j = n; j >= v[i]; j--) {
                        if (dp[j] < dp[j - v[i]] + w[i]) {
                            dp[j] = dp[j - v[i]] + w[i];

                        }
                    }
                }
            }

            System.out.println(dp[n]);
        }
    }
}

原文地址：https://www.cnblogs.com/ls-pankong/p/10490891.html