Given a string, determine if it is a palindrome, considering only alphanumeric characters and ignoring cases.
For example,
"A man, a plan, a canal: Panama" is a palindrome.
"race a car" is not a palindrome.
Note: Have you consider that the string might be empty? This is a good question to ask during an interview.
For the purpose of this problem, we define empty string as valid palindrome.
题目大意
给定一个字符串,判断是不是回文,只考虑字母数字字符,并不顾大小写。另外,空串被认为是有效的回文。
难度系数:容易
实现
bool isAlphanumeric(const char c) {
if (‘A‘ <= c && c <= ‘Z‘)
return true;
else if (‘a‘ <= c && c <= ‘z‘)
return true;
else if (‘0‘ <= c && c <= ‘9‘)
return true;
return false;
}
char toLower(const char c)
{
if (‘A‘ <= c && c <= ‘Z‘)
return ‘a‘ + c - ‘A‘;
return c;
}
bool isPalindrome(string s)
{
if (s.empty())
return true;
int begin = 0;
int end = s.size() - 1;
while (true) {
while (begin < s.size() && !isAlphanumeric(s[begin])){
begin++;
}
while (end >= 0 && !isAlphanumeric(s[end])) {
end--;
}
if (end <= begin)
return true;
if (toLower(s[begin]) != toLower(s[end])){
return false;
}
begin++;
end--;
}
}
时间: 2024-10-10 11:29:16