create table SatSun([id] int identity(1,1),[date] datetime,[weekday] char(6))
go
declare @datetime datetime,@weekday char(6)
set @datetime=‘2007-1-1‘
while @datetime<=‘2007-12-31‘
begin
select @weekday=datename(weekday,@datetime)
if @weekday= ‘星期六‘ insert SatSun([date],[weekday]) values(@datetime,@weekday)
if @weekday=‘星期日‘ insert SatSun([date],[weekday]) values(@datetime,‘星期天‘)
select @datetime=dateadd(day,1,@datetime)
end
go
select * from satsun
drop table satsun
/*
id date weekday
----------- ------------------------------------------------------ -------
1 2007-01-06 00:00:00.000 星期六
2 2007-01-07 00:00:00.000 星期天
3 2007-01-13 00:00:00.000 星期六
4 2007-01-14 00:00:00.000 星期天
5 2007-01-20 00:00:00.000 星期六
6 2007-01-21 00:00:00.000 星期天
7 2007-01-27 00:00:00.000 星期六
8 2007-01-28 00:00:00.000 星期天
9 2007-02-03 00:00:00.000 星期六
……
100 2007-12-16 00:00:00.000 星期天
101 2007-12-22 00:00:00.000 星期六
102 2007-12-23 00:00:00.000 星期天
103 2007-12-29 00:00:00.000 星期六
104 2007-12-30 00:00:00.000 星期天
*/（所影响的行数为 104 行）
****************************************************************************
declare @t table(dd datetime)
declare @d1 datetime
select @d1=‘2007-1-1‘
while(year(@d1) <2008)
begin
insert into @t select @d1
set @d1=dateadd(dd,1,@d1)
end
select * from @t where datepart(weekday,dd)=6 or datepart(weekday,dd)=7
****************************************************************************
declare @i int
declare @d datetime
set @i=1
set @d=‘2007-1-1‘
Create table #a (Dat datetime)
while year(@d)=2007
begin
insert into #a values (@d )
set @[email protected]+1
set @d=dateadd(day,1,@d)
end
select *,datepart(dw,Dat) as a from #a where datepart(dw,Dat) =1 or datepart(dw,Dat) =7
****************************************************************************
/*
功能: 计算在某一段时间内某周几（如星期一）的所有日期
设计：OK_008
时间：2006-10
*/
DECLARE @Date datetime
DECLARE @StartDate datetime
DECLARE @EndDate datetime
DECLARE @WeekDay int
DECLARE @i int
SET DATEFIRST 7 --设置每周的第一天
SET @StartDate=‘2006-01-01‘ --统计的开始日期
SET @EndDate=‘2006-12-31‘ --统计的结束日期
SET @WeekDay=1 --根据实际的@@DATEFIRST而定，一般默认是7，如 @StartDate=‘2006-01-01‘时候， @WeekDay=3表示星期二
SET @i=DATEPART(weekday,@StartDate)
PRINT ‘每周的第1天设置@@DATEFIRST: ‘+CAST(@@DATEFIRST AS nvarchar(1))
PRINT ‘开始日期对应一周的第几天: ‘+CAST(@i AS nvarchar(1))
IF(@i<[email protected] AND @i<7)
SET @[email protected]@i
ELSE IF(@i<[email protected] AND @i=7)
SET @[email protected]@WeekDay
ELSE
SET @[email protected]@[email protected][email protected]
SET @Date=DATEADD(day,@i,@StartDate)
WHILE @Date<[email protected]
BEGIN
IF(@StartDate<[email protected]) PRINT CONVERT(nvarchar(10),@Date,121)
SET @Date=DATEADD(Week,1,@Date)
END
GO
/* ==============运行结果================*/
/*
每周的第1天设置@@DATEFIRST: 7
开始日期对应一周的第几天: 1
2006-01-01
2006-01-08
2006-01-15
2006-01-22
2006-01-29
..........
*/
select dateadd(day,x,col),‘星期二‘ from
(
select cast(‘2006-1-1‘ as datetime) as col
)a cross join
(
SELECT top 365 b8.i+b7.i + b6.i + b5.i + b4.i +b3.i +b2.i + b1.i + b0.i x
FROM(SELECT 0 i UNION ALL SELECT 1) b0
CROSS JOIN(SELECT 0 i UNION ALL SELECT 2) b1
CROSS JOIN(SELECT 0 i UNION ALL SELECT 4) b2
CROSS JOIN(SELECT 0 i UNION ALL SELECT 8) b3
CROSS JOIN(SELECT 0 i UNION ALL SELECT 16) b4
CROSS JOIN(SELECT 0 i UNION ALL SELECT 32) b5
CROSS JOIN(SELECT 0 i UNION ALL SELECT 64) b6
CROSS JOIN(SELECT 0 i UNION ALL SELECT 128) b7
CROSS JOIN(SELECT 0 i UNION ALL SELECT 256) b8
order by 1
)b
where datepart(dw,dateadd(day,x,col))=3 (这个地方改值换取其他日期)
2006-01-03 00:00:00.000 星期二
2006-01-10 00:00:00.000 星期二
2006-01-17 00:00:00.000 星期二
2006-01-24 00:00:00.000 星期二
2006-01-31 00:00:00.000 星期二
****************************************************************************
DECLARE @t TABLE(date0 DATETIME)
DECLARE @st DATETIME,@et DATETIME
SET @st=‘2007-01-01‘
SET @et=‘2008-01-01‘
WHILE @st <@et
BEGIN
INSERT INTO @t VALUES(@st)
SELECT @st=DATEADD(DAY,1,@st)
END
SELECT date0,DATENAME(weekday,date0) FROM @t WHERE DATEPART(weekday,[email protected]@DATEFIRST-1) IN (6,7)
****************************************************************************
由于工作需要，在SQL Server 2005 下面写了一个计算两个日期之间相差工作日的函数。函数是以一个星期5天工作日计算，没有剔除五一国庆等假期。代码如下：
SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
-- =============================================
-- Author: Sinmen
-- Create date: 2007-11-01
-- Description: 计算两个日期之间相差的工作日
-- =============================================
ALTER FUNCTION [dbo].[WorkDatediff]
(
@begin_date datetime,
@end_date datetime
)
RETURNS int
AS
BEGIN
DECLARE @return_date_quantity int
DECLARE @temp datetime
DECLARE @week_quantity int
DECLARE @day_quantity int
DECLARE @begin_day_of_week int
DECLARE @end_day_of_week int
DECLARE @add_begin_day_quantity int
DECLARE @add_end_day_quantity int
set @day_quantity = Datediff(d,@begin_date,@end_date)
--判断传入的开始日期是否比结束日期大
if @day_quantity < 0
begin
set @temp = @begin_date
set @begin_date = @end_date
set @end_date = @temp
end
set @week_quantity = Abs(Datediff(ww,@begin_date,@end_date)) - 1
if @week_quantity < 0
set @week_quantity = 0
set @begin_day_of_week = Datepart(dw,@begin_date) - 1
set @end_day_of_week = Datepart(dw,@end_date) - 1
set @add_begin_day_quantity = case
when @begin_day_of_week > 5 then 0
else 6 - @begin_day_of_week --(5 - @begin_day_of_week + 1)
end
set @add_end_day_quantity = case
when abs(@day_quantity) < 8 then 0
when @end_day_of_week > 5 then 5
else @end_day_of_week
end
if @day_quantity = 0
set @return_date_quantity = 0
else
set @return_date_quantity = @week_quantity * 5 + @add_begin_day_quantity + @add_end_day_quantity
if @day_quantity < 0
set @return_date_quantity = @return_date_quantity * -1
RETURN @return_date_quantity
END
GO
SET ANSI_NULLS OFF
GO
SET QUOTED_IDENTIFIER OFF
GO