今日头条2017校招编程题

贪心？瞎搞  先排个序，然后扫一遍，边扫边维护一个数组v   v的长度为3    设vs数组的最后一个是x 如果abs(a[i]-x)大于10 那么贪心的策略我就 添加个v+10相应的ans++.

然后注意一些细节就好了...  我代码写的好挫

/* ***********************************************
Author        :guanjun
Created Time  :2016/9/21 19:50:13
File Name     :1001.cpp
************************************************ */
#include <iostream>
#include <cstring>
#include <cstdlib>
#include <stdio.h>
#include <algorithm>
#include <vector>
#include <queue>
#include <set>
#include <map>
#include <string>
#include <math.h>
#include <stdlib.h>
#include <iomanip>
#include <list>
#include <deque>
#include <stack>
#define ull unsigned long long
#define ll long long
#define mod 90001
#define INF 0x3f3f3f3f
#define maxn 10010
#define cle(a) memset(a,0,sizeof(a))
const ull inf = 1LL << 61;
const double eps=1e-5;
using namespace std;
priority_queue<int,vector<int>,greater<int> >pq;
struct Node{
    int x,y;
};
struct cmp{
    bool operator()(Node a,Node b){
        if(a.x==b.x) return a.y> b.y;
        return a.x>b.x;
    }
};

bool cmp(int a,int b){
    return a>b;
}
int a[100010];
int v[100010];
int main()
{
    #ifndef ONLINE_JUDGE
    freopen("in.txt","r",stdin);
    #endif
    //freopen("out.txt","w",stdout);
    int n;
    while(cin>>n){
        for(int i=1;i<=n;i++){
            scanf("%d",&a[i]);
        }
        sort(a+1,a+1+n);
        int ans=0;
        int cnt=0;
        for(int i=1;i<=n;i++){
        //    cout<<a[i]<<endl;
        int mark=0;
            if(cnt>=1&&cnt<3){
                int tmp=v[cnt];
                if(abs(tmp-a[i])>10){
                    ans++;v[++cnt]=tmp+10;
                    mark=1;
                }
                else{
                    v[++cnt]=a[i];
                }
            }
            else if(cnt==0){
                v[++cnt]=a[i];
            }
            if(cnt==3){
                if(mark)i--;
                cnt=0;
            }
        }
        if(cnt>0)ans+=3-cnt;
        printf("%d\n",ans);
    }
    return 0;
}