题目如下:
Given an integer array sorted in non-decreasing order, there is exactly one integer in the array that occurs more than 25% of the time.
Return that integer.
Example 1:
Input: arr = [1,2,2,6,6,6,6,7,10] Output: 6Constraints:
1 <= arr.length <= 10^4
0 <= arr[i] <= 10^5
解题思路:最直接的方法是统计每个元素出现的次数。
代码如下:
class Solution(object): def findSpecialInteger(self, arr): """ :type arr: List[int] :rtype: int """ dic = {} res = 0 for i in arr: dic[i] = dic.setdefault(i,0) + 1 if dic[i] > len(arr)/4: res = i break return res
原文地址:https://www.cnblogs.com/seyjs/p/12041875.html
时间: 2024-11-08 03:34:01