问题描述:
Thread thread1 = new Thread(new Runnable() {
public void run() {
for (int i = 0; i < 1000; i++) {
System.out.println(Thread.currentThread().getName() + "...." + i);
}
}
});
Thread thread2 = new Thread(new Runnable() {
public void run() {
for (int i = 0; i < 1000; i++) {
System.out.println(Thread.currentThread().getName() + "...." + i);
}
}
});
thread1.start();
thread2.start();
运行结果:可见多线程运行是没有顺序的
Thread-1....0
Thread-1....1
Thread-1....2
Thread-2....0
Thread-1....3
Thread-1....4
Thread-1....5
Thread-1....6
方法1:join
解释:join源码中执行的是Object类中的wait方法。原理是让主线程处于wait,知道子线程执行结束才继续执行主线程。
thread1.start();
thread1.join();
thread2.start();
thread2.join();
方法2:利用单线程池Executors.newSingleThreadExecutor()
ExecutorService executor = Executors.newSingleThreadExecutor();
executor.submit(thread1);
executor.submit(thread2);
executor.submit(thread3);
executor.shutdown();
原文地址:https://www.cnblogs.com/yejiang/p/12142792.html
时间: 2024-11-07 08:46:56