SSMS For Beginner Part 34

Part 1 Connecting to SQL Server using SSMS note that,SSMS is a client tool and not the server by itself,it is a developer machines connects to SQL Server. Part 2 Creating altering and dropping a database you cannot drop a database , if it is currentl

Part 28 Cast and Convert functions in SQL Server Part 29 Mathematical functions in sql server Part 30 Scalar user defined functions in sql server Part 31 Inline table valued functions in sql server Part 32 Multi statement table valued functions in sq

Part 18 Stored procedures in sql server Part 19 Stored procedures with output parameters Part 20 Stored procedure output parameters or return values Part 21 Advantages of stored procedures

Part 22 Built in string functions in sql server 2008 Part 23 LEFT, RIGHT, CHARINDEX and SUBSTRING functions in sql server Part 24 Replicate, Space, Patindex, Replace and Stuff string functions in sql server 2008

Part 25 DateTime functions in SQL Server Part 26 IsDate, Day, Month, Year and DateName DateTime functions in SQL Server Part 27 DatePart, DateAdd and DateDiff functions in SQL Server

Java面试题 Java面试题 1 1.面向对象的特征有哪些方面? 6 2.访问修饰符public,private,protected,以及不写(默认)时的区别? 7 3.String 是最基本的数据类型吗? 8 4.float f=3.4;是否正确? 8 5.short s1 = 1; s1 = s1 + 1;有错吗?short s1 = 1; s1 += 1;有错吗? 8 6.Java有没有goto? 8 7.int和Integer有什么区别? 9 8.&和&&的区别? 11

Zipline Beginner Tutorial Basics Zipline is an open-source algorithmic trading simulator written in Python .Zipline是一个用Python编写的开源算法交易模拟器. The source can be found at: https://github.com/quantopian/zipline 源码地址在 Some benefits include: 一些优势包括: Realisti

AtCoder Beginner Contest 103 D 题目大意:n个点,除第n个点外第i与第i+1个点有一条边,给定m个a[i],b[i],求最少去掉几条边能使所有a[i],b[i]不相连. 按右端点从小到大排序,如果当前选的去掉的边在区间内,那么符合条件,否则ans++,并贪心地把去掉的边指向右端点,因为前面的区间都满足条件了,所以要去掉的边要尽量向右移使其满足更多的区间. 1 #include <iostream> 2 #include <cstdio> 3 #incl

题目链接:AtCoder Beginner Contest 161 原版题解链接:传送门 A - ABC Swap 这题太水,直接模拟即可. 1 #include <iostream> 2 using namespace std; 3 int main() { 4 int a, b, c; 5 cin >> a >> b >> c; 6 swap(a, b); 7 swap(a, c); 8 cout << a << " &