界面实现rsa

今天去答辩，老师叫我回去做一个界面。我想问，老师，不是说话第一类的不做界面么现在又要做界面是什么回事？

╮(╯▽╰)╭  算了八  还是好好的敲代码八 下面就是修改过后的。  用SDK写的界面。

#include <windows.h>
#include "resource.h"
#include<tchar.h>
#include <stdio.h>
#include <math.h>
#include <windowsx.h>
int length = 0;
 char str2[20]={0};
static long int e ,n ,m,c,d;
HINSTANCE hins ;
TCHAR cD[20][30];
int flag = 0,str3[20]={0};
BOOL CALLBACK DlgMain(HWND hwnd,UINT message,WPARAM  wParam,    LPARAM  lParam);
bool JudgeP (int prime)             //判断是不是素数
{
    int i=0;
    long double temp=0 ;
    if (prime == 0||prime == 2)
        return false;
    else
    {
    temp =sqrt((float)prime);
    for (i=2;i<=temp;i++)
    {
        if (prime%i == 0)
                return false;       //输入的不是素数
    }
    return true ;                    //输入的数是素数
    }

}
int gcd(int a , int b){
    return b==0?a:gcd(b,a%b);
}
bool  CheckE ( int f_n ,int e)        //判断e是否符合要求  1<e <f_n且e 与f_n互素
{
    int k ;

    while (e > f_n || e<= 1)                        //确定e的范围
    {
        return false;
    }
    k =gcd(f_n,e) ;
       if ( k !=1)
           return false;
       return  true ;
}
long int  CalculateD(long int  f_n ,long  int e)     //辗转相除
{
    int i , j = 1 , t1 , t2= 1 , k = 0  , m ;

    int arry_1[30] = {f_n,e} ,arry_2[30] ={0} ;
    printf(" the Calculation:\n") ;
    for (i=1 ;arry_1[i] != 1; i ++)                //用数组存放好辗转相除过程中的数据
    {
        arry_1[i+1] =arry_1[i-1]%arry_1[i] ;
        arry_2 [i-1] = arry_1[i-1]/arry_1[i] ;
        wsprintf(cD[i],L" %d = %d*%d+%d\n",arry_1[i-1],arry_1[i],arry_2[i-1],arry_1[i+1] ) ;
    }
    flag = i;
    t1 = 1 ;
    t2 = -arry_2[i-2] ;
    while((i-2)!=0 )
    {
        m = t1 ;
        t1 = t2  ;
        if (j%2 != 0)
            t2 = (abs(m)+arry_2[i-3]*abs(t2));
        else
            t2 = -(abs(m)+arry_2[i-3]*abs(t2));
        i -- ;
        j++ ;
    }

    while(t2 < 0)    //保证D是大于0正数
    {
        t2 = f_n + t2 ;
    }
    k = t2 ;
    while(t2 = t2/f_n)
    {
        k = t2%f_n      ;
    }
    printf("D = %d\n",k);

    return k ;
}
int  * Dec2Bin(int e ) //转换为二进制
 {
  int i = 0 ;
  int str1[20];
 while(e)
 {
  str1[i] = e%2 ;
  e = e/2 ;
   i++ ;
 }
 i -- ;
 for (length = 0 ; i>=0 ; length ++)          //这里赋值的。Ok
 {
 str2[length] = str1[i] +‘0‘;   //这里是二进制的  只有10
 str3[length] = str1[i];
 i -- ;
 }
 str2[length]=‘\0‘;
 return str3 ;
 }
int  Encrypt(int m , int e , int n)  //平方乘法
 {
     int  c =1  , i ;
     int *p =  Dec2Bin(e) ;

     for (i = 0  ; i < length;i ++)
     {
         c = c %n;
         c =c*c%n ;
          if (*(p+i) == 1)
         { c =c%n;
          c =c*m%n;
          }
     }
     return c ;
 }
int WINAPI WinMain(    HINSTANCE hInstance,HINSTANCE hPrevInst, LPSTR lpszCmdLine,    int    nCmdShow)
{

    DialogBox(hInstance,(LPCWSTR)IDD_DIALOG1,NULL,DlgMain);
    return 0 ;
}
BOOL CALLBACK DlgEncrpty(HWND hwnd,UINT message,WPARAM  wParam,    LPARAM  lParam)
{
    TCHAR mesg[20] ={L""};
    TCHAR buff[512] ={L""};//最好不要用L 用TEXT
    switch (message)
    {
    case WM_INITDIALOG:
        wsprintf(mesg,L"(%d,%d)",e ,n );
        SetDlgItemText(hwnd,IDC_EDIT1,mesg);
        SetDlgItemTextA(hwnd,IDC_EDIT2,str2);
        SetDlgItemInt(hwnd,IDC_EDIT3,c,TRUE);
        break;
    case WM_DESTROY:
        ShowWindow(hwnd,SW_HIDE);
        break;
    case WM_CLOSE:
        ShowWindow(hwnd,SW_HIDE);
        break;
    }
    return 0 ;
}
BOOL CALLBACK DlgDecrption(HWND hwnd,UINT message,WPARAM  wParam,    LPARAM  lParam)
{
    HWND hlist =GetDlgItem(hwnd,IDC_LIST1);
    TCHAR mesg[20] ={L""};
    TCHAR buff[512] ={L""};//最好不要用L 用TEXT
    switch (message)
    {
    case WM_INITDIALOG:
        wsprintf(mesg,L"(%d,%d)",e ,n );
        SetDlgItemText(hwnd,IDC_EDIT1,mesg);
        SetDlgItemTextA(hwnd,IDC_EDIT2,str2);
        SetDlgItemInt(hwnd,IDC_EDIT3,m,TRUE);

        for (int i=0;i< flag;i++)
        {
            ListBox_AddString(hlist,cD[i]);
        }
        break;
    case WM_DESTROY:
        ShowWindow(hwnd,SW_HIDE);
        break;
    case WM_CLOSE:
        ShowWindow(hwnd,SW_HIDE);
        break;
    }
    return 0 ;
}
BOOL CALLBACK DlgMain(HWND hwnd,UINT message,WPARAM  wParam,    LPARAM  lParam)
{
    long int p,q ,f_n;
    int choice = 0;
    BOOL flag ;
            switch(message)
        {

            case  WM_COMMAND:
                switch (LOWORD(wParam))
                {
                case IDOK:
                    p = GetDlgItemInt(hwnd,IDC_EDIT1,&flag,TRUE);
                    if (!JudgeP(p))
                    MessageBox(hwnd,L"p不是素数",L"警告",MB_OK);
                    else
                    {
                    q =GetDlgItemInt(hwnd,IDC_EDIT2,&flag,TRUE);
                                        if (!JudgeP(q))
                                        {
                    MessageBox(hwnd,L"q不是素数",L"警告",MB_OK);
                                        }
                                        else
                                        {
                                            f_n =(p-1)*(q-1);
                    e =GetDlgItemInt(hwnd,IDC_EDIT3,&flag,TRUE);
                    if (!CheckE(f_n,e))
                        MessageBox(hwnd,L"请注意e的范围 而且e要与(p-1)*(q-1)互素",L"错误",MB_OK);
                    else
                    {
                    choice =IsDlgButtonChecked(hwnd,IDC_RADIO3);
                    choice = IsDlgButtonChecked(hwnd,IDC_RADIO4);
                    n = p*q ;
                    switch (choice)
                    {
                    case 0:                           //加密
                        m =GetDlgItemInt(hwnd,IDC_EDIT4,&flag,TRUE);
                        c =Encrypt(m,e,n);
                        DialogBox(hins,(LPCWSTR)IDD_DIALOG2,NULL,DlgEncrpty);
                        break;
                    case 1:                          //解密
                        c = GetDlgItemInt(hwnd,IDC_EDIT5,&flag,TRUE);
                        d=CalculateD(f_n,e);
                        m=Encrypt(c,d,n);
                        DialogBox(hins,(LPCWSTR)IDD_DIALOG3,NULL,DlgDecrption);
                        break;
                    }
                    }}
                                                            }
                    break;
                }
                break;
            case WM_DESTROY:
            PostQuitMessage(0);                    //调用PostQuitMessage发出WM_QUIT消息
            break;
            case WM_CLOSE:
                DestroyWindow(hwnd);
                break;
        }
    return 0;
}

在这个遇到的那题是  如何一个int型的数组放到edit空间输出。表示脑袋太笨，很久才做出来。噗。。

实现主界面：

输出加密后的界面：

输出界面的界面：