错误的代码

HttpClient httpclient = new DefaultHttpClient();

HttpUriRequest request = new HttpGet(uri);

HttpParams p = new BasicHttpParams();

p.setParameter("param", "value");

request.setParams(p);
request.setHeader("Accept", "application/json, text/javascript, */*; q=0.01");
HttpResponse response = null;
try {

    response = httpclient.execute(request);

} catch (ClientProtocolException e) {

    e.printStackTrace();

}

解决方案

HttpClient httpclient = new DefaultHttpClient();

String url = "http://example.com";

List<NameValuePair> params = new ArrayList<NameValuePair>();

params.add( new BasicNameValuePair( "param", "value" ) );

URI uri = new URI( url + "?" + URLEncodedUtils.format( params, "utf-8" );
HttpUriRequest request = new HttpGet(uri);
request.setHeader("Accept", "application/json, text/javascript, */*; q=0.01");
HttpResponse response = null;
try {

    response = httpclient.execute(request);

} catch (ClientProtocolException e) {

    e.printStackTrace();

}

HttpGet params not being sent
httpget.setParams(params)不好使