脚本学习,多写写就会啦,来一发个人编写的超级无敌low的子域名查询脚本
#coding:utf-8 import re import requests import urllib import urllib2 import bs4 from bs4 import BeautifulSoup key=raw_input("please input top domain: ") print "查询马上开始..." title=[] domainlist=[] for n in xrange(1,66): if n!=1: n*=10 url="https://cn.bing.com/search?q=domain:"+key+"&first=%s" % n try: req=urllib2.Request(url) resp=urllib2.urlopen(req).read() #BeautifulSoup匹配标题 bsObj=BeautifulSoup(resp,"lxml") getList=bsObj.find_all("h2",{"class":""}) for t in getList: title.append(t.get_text()) #正则匹配子域名 regex=re.compile(‘<cite>(.*?)</cite>‘).findall(resp) for i in regex: domainlist.append(i.strip(‘https://‘).strip(‘http://‘).split(‘/‘)[0]) #同步输出查询到的标题和子域名 for (i,j) in zip(title,domainlist): print "%-50s%-30s" % (i,j) except Exception,e: print e print "查询已全部完成..." #去掉重复的子域名 domainlists=list(set(domainlist)) #保存子域名 for line in domainlists: with open(‘subdomain.txt‘,‘a‘) as fw: fw.write(line+‘\n‘)
运行截图:
运行结果截图:
原文地址:https://www.cnblogs.com/peterpan0707007/p/8831183.html
时间: 2024-10-01 14:46:31