三元运算
三元运算(三目运算),是对简单的条件语句的缩写
# 书写格式 result = 值1 if 条件 else 值2 # 如果条件成立,那么将 “值1” 赋值给result变量,否则,将“值2”赋值给result变量
基本数据类型补充
set
set集合,是一个无序且不重复的元素集合
class set(object): """ set() -> new empty set object set(iterable) -> new set object Build an unordered collection of unique elements. """ def add(self, *args, **kwargs): # real signature unknown """ Add an element to a set,添加元素 This has no effect if the element is already present. """ pass def clear(self, *args, **kwargs): # real signature unknown """ Remove all elements from this set. 清除内容""" pass def copy(self, *args, **kwargs): # real signature unknown """ Return a shallow copy of a set. 浅拷贝 """ pass def difference(self, *args, **kwargs): # real signature unknown """ Return the difference of two or more sets as a new set. A中存在,B中不存在 (i.e. all elements that are in this set but not the others.) """ pass def difference_update(self, *args, **kwargs): # real signature unknown """ Remove all elements of another set from this set. 从当前集合中删除和B中相同的元素""" pass def discard(self, *args, **kwargs): # real signature unknown """ Remove an element from a set if it is a member. If the element is not a member, do nothing. 移除指定元素,不存在不保错 """ pass def intersection(self, *args, **kwargs): # real signature unknown """ Return the intersection of two sets as a new set. 交集 (i.e. all elements that are in both sets.) """ pass def intersection_update(self, *args, **kwargs): # real signature unknown """ Update a set with the intersection of itself and another. 取交集并更更新到A中 """ pass def isdisjoint(self, *args, **kwargs): # real signature unknown """ Return True if two sets have a null intersection. 如果没有交集,返回True,否则返回False""" pass def issubset(self, *args, **kwargs): # real signature unknown """ Report whether another set contains this set. 是否是子序列""" pass def issuperset(self, *args, **kwargs): # real signature unknown """ Report whether this set contains another set. 是否是父序列""" pass def pop(self, *args, **kwargs): # real signature unknown """ Remove and return an arbitrary set element. Raises KeyError if the set is empty. 移除元素 """ pass def remove(self, *args, **kwargs): # real signature unknown """ Remove an element from a set; it must be a member. If the element is not a member, raise a KeyError. 移除指定元素,不存在保错 """ pass def symmetric_difference(self, *args, **kwargs): # real signature unknown """ Return the symmetric difference of two sets as a new set. 对称差集 (i.e. all elements that are in exactly one of the sets.) """ pass def symmetric_difference_update(self, *args, **kwargs): # real signature unknown """ Update a set with the symmetric difference of itself and another. 对称差集,并更新到a中 """ pass def union(self, *args, **kwargs): # real signature unknown """ Return the union of sets as a new set. 并集 (i.e. all elements that are in either set.) """ pass def update(self, *args, **kwargs): # real signature unknown """ Update a set with the union of itself and others. 更新 """ pass
练习:寻找差异
#!/usr/bin/env python # -*-coding:utf-8 -*- old_dict = { "#1":11, "#2":22, "#3":100, } new_dict = { "#1":33, "#4":22, "#7":100, } old_set = set(old_dict.keys()) new_set = set(new_dict.keys()) same_set = old_set.intersection(new_set) up_set = new_set.difference(old_set) ret_dict = {} for k in same_set: ret_dict[k]=new_dict[k] for i in up_set: ret_dict[i]=new_dict[i] print(ret_dict) # print(old_set) # print(new_set)
深浅拷贝
一、数字和字符串
对于 数字 和 字符串 而言,赋值、浅拷贝和深拷贝无意义,因为其永远指向同一个内存地址。
import copy a = 132 b = ‘Ales‘ # ## 浅拷贝 ## aa = copy.copy(a) bb = copy.copy(b) # ## 深拷贝 ## aaa = copy.deepcopy(a) bbb = copy.deepcopy(b) print(id(a),id(aa),id(aaa)) print(id(b),id(bb),id(bbb)) # ## 1691783456 1691783456 1691783456 # ## 47227376 47227376 47227376
二、其他基本数据类型
对于字典、元祖、列表 而言,进行赋值、浅拷贝和深拷贝时,其内存地址的变化是不同的。
1、赋值
赋值,只是创建一个变量,该变量指向原来内存地址,如:
n1 = {"k1": "wu", "k2": 123, "k3": ["alex", 456]} n2 = n1
2、浅拷贝
浅拷贝,在内存中只额外创建第一层数据
import copy n1 = {"k1": "wu", "k2": 123, "k3": ["alex", 456]} n3 = copy.copy(n1) print(id(n1),id(n3)) print(id(n1["k1"]),id(n3["k1"])) # 44947080 45383304 # 45327056 45327056
3、深拷贝
深拷贝,在内存中将所有的数据重新创建一份(排除最后一层,即:python内部对字符串和数字的优化)
import copy n1 = {"k1": "wu", "k2": 123, "k3": ["alex", 456]} n4 = copy.deepcopy(n1) print(id(n1),id(n4)) print(id(n1["k3"]),id(n4["k3"])) print(id(n1["k3"][0]),id(n4["k3"][0])) # 56088200 56460680 # 58962760 58930696 # 56506216 56506216
函数
时间: 2024-12-09 13:54:58