plsqL复习

1. 下单超过4次的女顾客的查询语句：

   SELECT c.customer_id, COUNT(o.order_id) AS orders_ct

   FROM customers c

   JOIN orders o

   ON c.customer_id = o.customer_id

   WHERE c.gender = ‘F‘

   GROUP BY c.customer_id

   HAVING COUNT(o.order_id) > 4

   8   ORDER BY orders_ct, c.customer_id

   9  ;

   CUSTOMER_ID ORDERS_CT

   ----------- ---------

   $146   $5

   $147   $5

2. SELECT c.customer_id cust_id, o.order_id ord_id, c.gender

   FROM customers c

JOIN orders o

ON c.customer_id = o.customer_id ;

CUST_ID    ORD_ID G

--------- --------- -

$147     $2450 F

$147     $2425 F

$147     $2385 F

$147     $2366 F

$147     $2396 F

$148     $2451 M

$148     $2426 M

$148     $2386 M

$148     $2367 M

3.Group by语句：

SELECT c.customer_id, COUNT(o.order_id) AS orders_ct

FROM customers c

JOIN orders o

ON c.customer_id = o.customer_id

WHERE gender = ‘F‘

GROUP BY c.customer_id;

CUSTOMER_ID ORDERS_CT

----------- ---------

$123   $1

$147   $5

$107   $4

$154   $1

$169   $1

$104   $4

$105   $4

$146   $5

$156   $1

$166   $1

$103   $4

11 rows selected.

4.Select列表：

SELECT c.customer_id,

c.cust_first_name || ‘‘ || c.cust_last_name,

(SELECT e.last_name

FROM hr.employees e

WHERE e.employee_id = c.account_mgr_id) acct_mgr

FROM oe.customers c;

CUSTOMER_ID C.CUST_FIRST_NAME||‘‘||C.CUST_LAST_NAME  ACCT_MGR

----------- ---------------------------------------- -------------------------

$147 IshwaryaRoberts     Russell

$148 GustavSteenburgen     Russell

$149 MarkusRampling     Russell

$150 GoldieSlater     Russell

$151 DivineAykroyd     Russell

$152 DieterMatthau     Russell

$153 DivineSheen     Russell

$154 FredericGrodin     Russell

$155 FredericoRomero     Russell

5.INSERT语句：

INSERT INTO hr.jobs

(job_id, job_title, min_salary, max_salary)

VALUES

(‘IT_PM‘, ‘Project Manager‘, 5000, 11000);

1 row created.

SQL> commit;

Commit complete.

6.多表查询：

SQL> select * from large_customers;

no rows selected

SQL> select * from medium_customers;

no rows selected

SQL> select * from small_customers;

no rows selected

INSERT ALL WHEN sum_orders < 10000 THEN INTO small_customers WHEN sum_orders >= 10000 AND sum_orders < 100000 THEN INTO medium_customers ELSE INTO large_customers

SELECT customer_id, SUM(order_total) sum_orders

FROM orders

GROUP BY customer_id;