【ESCAPE PLAN】逃離

p.MsoNormal { margin: 0pt; margin-bottom: .0001pt; text-align: justify; font-family: "Times New Roman"; font-size: 10.5000pt } h3 { margin-top: 5.0000pt; margin-bottom: 5.0000pt; text-align: left; font-family: 宋体; font-weight: bold; font-size: 1

Fire! Time Limit: 1000MS   Memory Limit: Unknown   64bit IO Format: %lld & %llu Submit Status Description Problem B: Fire! Joe works in a maze. Unfortunately, portions of the maze have caught on fire, and the owner of the maze neglected to create a f

题目描述: Joe works in a maze. Unfortunately, portions of the maze have caught on fire, and the owner of the maze neglected to create a fire escape plan. Help Joe escape the maze. Given Joe's location in the maze and which squares of the maze are on fire

Joe works in a maze.  Unfortunately, portions of the maze havecaught on  re, and the owner of the maze neglected to create a  reescape plan. Help Joe escape the maze.Given Joe's location in the maze and which squares of the mazeare on  re, you must d

Description Joe works in a maze. Unfortunately, portions of the maze have caught on fire, and the owner of the maze neglected to create a fire escape plan. Help Joe escape the maze. Given Joe's location in the maze and which squares of the maze are o

一直拖.放了放久.受不了 A - 棋盘问题 Time Limit:1000MS     Memory Limit:10000KB     64bit IO Format:%I64d & %I64u Submit Status Description 在一个给定形状的棋盘(形状可能是不规则的)上面摆放棋子,棋子没有区别.要求摆放时任意的两个棋子不能放在棋盘中的同一行或者同一列,请编程求解对于给定形状和大小的棋盘,摆放k个棋子的所有可行的摆放方案C. Input 输入含有多组测试数据. 每组数据的第

题目链接 Problem B: Fire! Joe works in a maze. Unfortunately, portions of the maze have caught on fire, and the owner of the maze neglected to create a fire escape plan. Help Joe escape the maze. Given Joe's location in the maze and which squares of the

11624 Fire!Joe works in a maze. Unfortunately, portions of the maze have caughton fire, and the owner of the maze neglected to create a fire escape plan.Help Joe escape the maze.Given Joe’s location in the maze and which squares of the maze areon fir

解题报告 思路: 从s->t 再从t->s等同与s->t两次,要求每条路只能走一次,要求最小花费,让每一条边容量为1,跑跑费用流 只要跑出流量为2就结束. #include <iostream> #include <cstring> #include <cstdio> #include <queue> #define inf 0x3f3f3f3f #define N 5000 #define M 50000 using namespace