Lweb and String

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)
Total Submission(s): 492    Accepted Submission(s): 312

Problem Description

Lweb has a string S.

Oneday, he decided to transform this string to a new sequence.

You need help him determine this transformation to get a sequence which has the longest LIS(Strictly Increasing).

You need transform every letter in this string to a new number.

A is the set of letters of S, B is the set of natural numbers.

Every injection f:A→B can be treat as an legal transformation.

For example, a String “aabc”, A={a,b,c}, and you can transform it to “1 1 2 3”, and the LIS of the new sequence is 3.

Now help Lweb, find the longest LIS which you can obtain from S.

LIS: Longest Increasing Subsequence. (https://en.wikipedia.org/wiki/Longest_increasing_subsequence)

Input

The first line of the input contains the only integer T,(1≤T≤20).

Then T lines follow, the i-th line contains a string S only containing the lowercase letters, the length of S will not exceed 105.

Output

For each test case, output a single line "Case #x: y", where x is the case number, starting from 1. And y is the answer.

Sample Input

2

aabcc

acdeaa

Sample Output

Case #1: 3

Case #2: 4

ccpc网赛的签到题，题意不是最长上升子序列

 1 //2016.8.16
 2 #include<iostream>
 3 #include<cstdio>
 4 #include<set>
 5
 6 using namespace std;
 7
 8 set<int> st;
 9
10 int main()
11 {
12     int T, kase = 0;
13     string s;
14     cin>>T;
15     while(T--)
16     {
17         cin>>s;
18         st.clear();
19         for(int i = 0; i < s.size(); i++)
20         {
21             st.insert(s[i]);
22         }
23         printf("Case #%d: ", ++kase);
24         cout<<st.size()<<endl;
25     }
26
27     return 0;
28 }