UVA10976

题目

分析:x>=y故1/y>=1/x,1/k-1/y<=1/y,所以可知道y<=2k，然后通过y去求解x即可

 1 #include "iostream"
 2 #include "cstdio"
 3 #include "cstring"
 4 #include "vector"
 5 using namespace std;
 6 int k;
 7 int main()
 8 {
 9     while(cin>>k)
10     {
11         vector<int> que1,que2;
12         for(int i=k+1;i<=(2*k);i++){
13             if(i*k%(i-k)==0){
14                 que1.push_back(i);
15                 que2.push_back(i*k/(i-k));
16             }
17         }
18         int t=que1.size();
19         printf("%d\n",t);
20         for(int i=0;i<que1.size();i++){
21             printf("1/%d = 1/%d + 1/%d\n",k,que2[i],que1[i]);
22         }
23     }
24 }