目录
- 目录
- 题目
- 思路
- AC SQL
题目
Given a Weather table, write a SQL query to find all dates’ Ids with higher temperature compared to its previous (yesterday’s) dates.
Id(INT) | Date(DATE) | Temperature(INT) |
---|---|---|
1 | 2015-01-01 | 10 |
2 | 2015-01-02 | 25 |
3 | 2015-01-03 | 20 |
4 | 2015-01-04 | 30 |
For example, return the following Ids for the above Weather table:
Id |
---|
2 |
4 |
思路
这是一道很简单的sql题目,考察的是数据库表联接知识。可以参考我之前的一篇博客:数据库表连接
同时,介绍一个Mysql的函数:
TO_DAYS(date):给定一个日期data,返回从年份0开始的天数
AC SQL
select w1.Id from Weather as w1 inner join Weather as w2 on TO_DAYS(w1.Date) = TO_DAYS(w2.Date) + 1 and w1.Temperature > w2.Temperature;
时间: 2024-10-07 13:59:08