线段树 Codeforces Round #197 (Div. 2) D. Xenia and Bit Operations

题目传送门

 1 /*
 2     线段树的单点更新：有一个交叉更新，若rank=1，or；rank=0，xor
 3     详细解释：http://www.xuebuyuan.com/1154895.html
 4 */
 5 #include <cstdio>
 6 #include <iostream>
 7 #include <algorithm>
 8 #include <cstring>
 9 #include <string>
10 #include <cmath>
11 #include <set>
12 #include <map>
13 using namespace std;
14 #define lson l, mid, rt << 1
15 #define rson mid+1, r, rt << 1 | 1
16
17 const int MAXN = 1 << 17 | 1;
18 const int INF = 0x3f3f3f3f;
19 struct NODE
20 {
21     int v, mx, mn, sum;
22     int rank;
23 }node[MAXN << 2];
24
25 void push_up(int rt)
26 {
27     if (node[rt<<1].rank == 1)
28     {
29         node[rt].rank = 0;
30         node[rt].v = node[rt<<1].v | node[rt<<1|1].v;
31     }
32     else
33     {
34         node[rt].rank = 1;
35         node[rt].v = node[rt<<1].v ^ node[rt<<1|1].v;
36     }
37 }
38
39
40 void build(int l, int r, int rt)
41 {
42     if (l == r)
43     {
44         scanf ("%d", &node[rt].v);
45         node[rt].rank = 1;
46         return ;
47     }
48     int mid = (l + r) >> 1;
49     build (lson);
50     build (rson);
51
52     push_up (rt);
53 }
54
55 void updata(int p, int b, int l, int r, int rt)
56 {
57     if (l == r)
58     {
59         node[rt].v = b;
60         return ;
61     }
62     int mid = (l + r) >> 1;
63     if (p <= mid)    updata (p, b, lson);
64     else    updata (p, b, rson);
65
66     push_up (rt);
67 }
68
69
70 int main(void)        //Codeforces Round #197 (Div. 2) D. Xenia and Bit Operations
71 {
72     //freopen ("H.in", "r", stdin);
73
74     int n, m;
75     scanf ("%d%d", &n, &m);
76     build (1, 1<<n, 1);
77
78     int p, b;
79     for (int i=1; i<=m; ++i)
80     {
81         scanf ("%d%d", &p, &b);
82         updata (p, b, 1, 1<<n, 1);
83         printf ("%d\n", node[1].v);
84     }
85
86     return 0;
87 }