java 删除字符串中的特定字符

    /**
     * Delete any character in a given String.
     * @param inString the original String
     * @param charsToDelete a set of characters to delete.
     * E.g. "az\n" will delete ‘a‘s, ‘z‘s and new lines.
     * @return the resulting String
     */
    public static String deleteAny(String inString, String charsToDelete) {
        if (!hasLength(inString) || !hasLength(charsToDelete)) {
            return inString;
        }
        StringBuilder sb = new StringBuilder();
        for (int i = 0; i < inString.length(); i++) {
            char c = inString.charAt(i);
            if (charsToDelete.indexOf(c) == -1) {
                sb.append(c);
            }
        }
        return sb.toString();
    }
    /**
     * Check that the given String is neither {@code null} nor of length 0.
     * Note: Will return {@code true} for a String that purely consists of whitespace.
     * @param str the String to check (may be {@code null})
     * @return {@code true} if the String is not null and has length
     * @see #hasLength(CharSequence)
     */
    public static boolean hasLength(String str) {
        return hasLength((CharSequence) str);
    }
    /**
     * Check that the given CharSequence is neither {@code null} nor of length 0.
     * Note: Will return {@code true} for a CharSequence that purely consists of whitespace.
     * <p><pre class="code">
     * StringUtils.hasLength(null) = false
     * StringUtils.hasLength("") = false
     * StringUtils.hasLength(" ") = true
     * StringUtils.hasLength("Hello") = true
     * </pre>
     * @param str the CharSequence to check (may be {@code null})
     * @return {@code true} if the CharSequence is not null and has length
     * @see #hasText(String)
     */
    public static boolean hasLength(CharSequence str) {
        return (str != null && str.length() > 0);
    }