不得不感叹,计算几何真是太美丽了!!
AC代码:
#include <cstdio> #include <cstring> #include <algorithm> #include <iostream> #include <cmath> using namespace std; struct Point { double x, y; Point(double x = 0, double y = 0) : x(x) , y(y) { } }; typedef Point Vector; Vector operator + (Vector A, Vector B) { return Vector(A.x+B.x, A.y+B.y); } Vector operator - (Vector A, Vector B) { return Vector(A.x-B.x, A.y-B.y); } Vector operator * (Vector A, double p) { return Vector(A.x*p, A.y*p); } Vector operator / (Vector A, double p) { return Vector(A.x/p, A.y/p); } bool operator < (const Point& a, const Point& b) { return a.x < b.x || (a.x == b.x && a.y < b.y); } const double eps = 1e-10; int dcmp(double x) { if(fabs(x) < eps) return 0; else return x < 0 ? -1 : 1; } bool operator == (const Point& a, const Point& b) { return dcmp(a.x - b.x) == 0 && dcmp(a.y - b.y) == 0; } double Dot(Vector A, Vector B) { return A.x*B.x + A.y*B.y; } double Length(Vector A) { return sqrt(Dot(A, A)); } double Angle(Vector A, Vector B) { return acos(Dot(A, B) / Length(A) / Length(B)); } double Cross(Vector A, Vector B) { return A.x*B.y - A.y*B.x; } double Area2(Point A, Point B, Point C) { return Cross(B-A, C-A); } Vector Rotate(Vector A, double rad) { return Vector(A.x*cos(rad) - A.y*sin(rad), A.x*sin(rad)+A.y*cos(rad) ); } Vector Normal(Vector A) { double L = Length(A); return Vector(-A.y/L, A.x/L); } Point GetLineIntersection(Point P, Vector v, Point Q, Vector w) { Vector u = P - Q; double t = Cross(w, u) / Cross(v, w); return P + v * t; } double DistanceToLine(Point P, Point A, Point B) { Vector v1 = B-A, v2 = P - A; return fabs(Cross(v1,v2) / Length(v1)); } double DistanceToSegment(Point P, Point A, Point B) { if(A==B) return Length(P-A); Vector v1 = B - A, v2 = P - A, v3 = P - B; if(dcmp(Dot(v1, v2)) < 0) return Length(v2); else if(dcmp(Dot(v1, v3)) > 0) return Length(v3); else return fabs(Cross(v1, v2)) / Length(v1); } Point GetLineProjection(Point P, Point A, Point B) { Vector v = B - A; return A + v * ( Dot(v, P-A) / Dot(v, v) ); } bool SegmentProperIntersection(Point a1, Point a2, Point b1, Point b2) { double c1 = Cross(a2 - a1, b1 - a1), c2 = Cross(a2 - a1, b2 - a1), c3 = Cross(b2 - b1, a1 - b1), c4 = Cross(b2 - b1, a2 - b1); return dcmp(c1) * dcmp(c2) < 0 && dcmp(c3) * dcmp(c4) < 0; } bool OnSegment(Point p, Point a1, Point a2) { return dcmp(Cross(a1 - p, a2 - p)) == 0 && dcmp(Dot(a1 - p, a2 - p)) < 0; } double ConvexPolygonArea(Point* p, int n) { double area = 0; for(int i = 1; i < n-1; i++) area += Cross(p[i] - p[0], p[i + 1] - p[0]); return area / 2; } const int maxn = 60; int T, A, B; Point P[maxn], Q[maxn]; double Min, Max; void update(Point P, Point A, Point B) { Min = min(Min, DistanceToSegment(P, A, B)); Max = max(Max, Length(P-A)); Max = max(Max, Length(P-B)); } int main() { scanf("%d", &T); for(int cas = 1; cas <= T; cas++) { scanf("%d %d", &A, &B); for(int i = 0; i < A; i++) scanf("%lf %lf", &P[i].x, &P[i].y); for(int i = 0; i < B; i++) scanf("%lf %lf", &Q[i].x, &Q[i].y); double lenA = 0, lenB = 0; for(int i = 0; i < A-1; i++) lenA += Length(P[i+1]-P[i]); for(int i = 0; i < B-1; i++) lenB += Length(Q[i+1]-Q[i]); int Sa = 0, Sb = 0;//Sa,Sb为刚经过的拐点的编号 Point Pa = P[0], Pb = Q[0];//Pa,Pb为甲乙现在的位置 Min = 1e9, Max = -1e9; while(Sa < A-1 && Sb < B-1) { double La = Length(P[Sa+1] - Pa);//甲到下一个拐点的距离 double Lb = Length(Q[Sb+1] - Pb);//乙到下一个拐点的距离 double T = min(La/lenA, Lb/lenB);//可以先让甲和乙的速度分别是lenA和lenB Vector Va = (P[Sa + 1] - Pa) / La * T * lenA;//甲的位移向量,(P[Sa+1]-Pa)/La为单位向量 Vector Vb = (Q[Sb + 1] - Pb) / Lb * T * lenB;//乙的位移向量,(Q[Sb+1]-Pb)/Lb为单位向量 update(Pa, Pb, Pb + Vb - Va); //更新最大最小距离 Pa = Pa + Va; Pb = Pb + Vb; if(Pa == P[Sa+1]) Sa++; if(Pb == Q[Sb+1]) Sb++; } printf("Case %d: %.0lf\n", cas, Max - Min);//%.0lf可以表达四舍五入 } return 0; }
时间: 2024-10-14 02:09:37