Table: Person
+-------------+---------+ | Column Name | Type | +-------------+---------+ | PersonId | int | | FirstName | varchar | | LastName | varchar | +-------------+---------+ PersonId is the primary key column for this table.
Table: Address
+-------------+---------+ | Column Name | Type | +-------------+---------+ | AddressId | int | | PersonId | int | | City | varchar | | State | varchar | +-------------+---------+ AddressId is the primary key column for this table.
Write a SQL query for a report that provides the following information for each person in the Person table, regardless if there is an address for each of those people:
FirstName, LastName, City, State
LeetCode还出了是来到数据库的题,来那么也来做做吧,这道题是第一道,相对来说比较简单,是一道两表联合查找的问题,我们需要用到Join操作,关于一些Join操作可以看我之前的博客SQL Left Join, Right Join, Inner Join, and Natural Join 各种Join小结,最直接的方法就是用Left Join来做,根据PersonId这项来把两个表联合起来:
解法一:
SELECT Person.FirstName, Person.LastName, Address.City, Address.State FROM Person LEFT JOIN Address ON Person.PersonId = Address.PersonId;
在使用Left Join时,我们也可以使用关键Using来声明我们相用哪个列名来进行联合:
解法二:
SELECT Person.FirstName, Person.LastName, Address.City, Address.State FROM Person LEFT JOIN Address USING(PersonId);
或者我们可以加上Natural关键字,这样我们就不用声明具体的列,MySQL可以自行搜索相同的列:
解法三:
SELECT Person.FirstName, Person.LastName, Address.City, Address.State FROM Person NATURAL LEFT JOIN Address;
参考资料:
https://leetcode.com/discuss/21216/its-a-simple-question-of-left-join-my-solution-attached
https://leetcode.com/discuss/53001/comparative-solution-between-left-using-natural-left-join
LeetCode All in One 题目讲解汇总(持续更新中...)
时间: 2024-10-13 00:56:42