Given an array of integers with possible duplicates, randomly output the index of a given target number. You can assume that the given target number must exist in the array. Note: The array size can be very large. Solution that uses too much extra space will not pass the judge. Example: int[] nums = new int[] {1,2,3,3,3}; Solution solution = new Solution(nums); // pick(3) should return either index 2, 3, or 4 randomly. Each index should have equal probability of returning. solution.pick(3); // pick(1) should return 0. Since in the array only nums[0] is equal to 1. solution.pick(1);
Reservior Sampling
1 public class Solution { 2 int[] arr; 3 Random random; 4 5 6 public Solution(int[] nums) { 7 arr = nums; 8 random = new Random(); 9 } 10 11 public int pick(int target) { 12 int count = 0; 13 int index = 0; 14 for (int i=0; i<arr.length; i++) { 15 if (arr[i] == target) { 16 count++; 17 if (random.nextInt(count) == 0) { 18 index = i; 19 } 20 } 21 } 22 return index; 23 } 24 } 25 26 /** 27 * Your Solution object will be instantiated and called as such: 28 * Solution obj = new Solution(nums); 29 * int param_1 = obj.pick(target); 30 */
时间: 2024-11-05 22:05:18