#Leet Code# Convert Sorted Array to Binary Search Tree

描述:递归

代码:

 1 class Solution:
 2     # @param num, a list of integers
 3     # @return a tree node
 4     def sortedArrayToBST(self, num):
 5         if len(num) == 0:
 6             return None
 7
 8         mid_index = len(num) / 2
 9
10         tmp_tree = TreeNode(num[mid_index])
11         tmp_tree.left = self.sortedArrayToBST(num[:mid_index])
12         tmp_tree.right = self.sortedArrayToBST(num[mid_index + 1:])
13
14         return tmp_tree

#Leet Code# Convert Sorted Array to Binary Search Tree

时间: 2024-08-03 00:20:47

#Leet Code# Convert Sorted Array to Binary Search Tree的相关文章

leetcode 108 Convert Sorted Array to Binary Search Tree

题目连接 https://leetcode.com/problems/convert-sorted-array-to-binary-search-tree/ Convert Sorted Array to Binary Search Tree Description Given an array where elements are sorted in ascending order, convert it to a height balanced BST. /** * Definition f

39.1: Convert Sorted Array to Binary Search Tree

/************************************************************************/            /*       39.1:  Convert Sorted Array to Binary Search Tree                               */            /************************************************************

Convert Sorted Array to Binary Search Tree & Convert Sorted List to Binary Search Tree

Convert Sorted Array to Binary Search Tree Given an array where elements are sorted in ascending order, convert it to a height balanced BST. 方法:将有序数组转为平衡二叉树,我们知道平衡二叉树的中序遍历是有序数组,而且“中间”的元素可以作为根节点,那么构建树的时候,找出中间元素,构造根元素,然后继续重复上面的方法,构造左子树和右子树.代码如下: 1 /**

[leetcode]Convert Sorted Array to Binary Search Tree @ Python

原题地址:http://oj.leetcode.com/problems/convert-sorted-array-to-binary-search-tree/ 题意:将一个排序好的数组转换为一颗二叉查找树,这颗二叉查找树要求是平衡的. 解题思路:由于要求二叉查找树是平衡的.所以我们可以选在数组的中间那个数当树根root,然后这个数左边的数组为左子树,右边的数组为右子树,分别递归产生左右子树就可以了. 代码: # Definition for a binary tree node # class

LeetCode OJ 108. Convert Sorted Array to Binary Search Tree DFS求解

题目链接:https://leetcode.com/problems/convert-sorted-array-to-binary-search-tree/ 108. Convert Sorted Array to Binary Search Tree My Submissions Question Total Accepted: 68378 Total Submissions: 187560 Difficulty: Medium Given an array where elements ar

Convert Sorted Array to Binary Search Tree leetcode java

题目: Given an array where elements are sorted in ascending order, convert it to a height balanced BST. 题解: 先复习下什么是二叉搜索树(引自Wikipedia): 二叉查找树(Binary Search Tree),也称有序二叉树(ordered binary tree),排序二叉树(sorted binary tree),是指一棵空树或者具有下列性质的二叉树: 若任意节点的左子树不空,则左子树

[Leetcode][JAVA] Convert Sorted Array to Binary Search Tree && Convert Sorted List to Binary Search Tree

Convert Sorted Array to Binary Search Tree Given an array where elements are sorted in ascending order, convert it to a height balanced BST. 很简单的二分法,只要给出Array的开始和结束下标作为参数传入即可. 1 public TreeNode sortedArrayToBST(int[] num) { 2 return constructBST(num,

LeetCode: Convert Sorted Array to Binary Search Tree [108]

[题目] Given an array where elements are sorted in ascending order, convert it to a height balanced BST. [题意] 给定一个已排序的数组(不存在重复元素),将它转换成一棵平衡二叉搜索树. [思路] 由于平衡二叉树要求左右子树的高度差绝对值相遇等于1,也就是说左右子树尽可能包含相同数目节点. 则使用二分法来解本题即可. [代码] /** * Definition for binary tree *

34. Convert Sorted List to Binary Search Tree && Convert Sorted Array to Binary Search Tree

Convert Sorted List to Binary Search Tree OJ: https://oj.leetcode.com/problems/convert-sorted-list-to-binary-search-tree/ Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST. 思想: 以中间点为根节点,按先序顺序