MZL‘s chemistry

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)

Problem Description

MZL define F(X) as
the first ionization energy of the chemical element X

Now he get two chemical elements U,V,given
as their atomic number,he wants to compare F(U) and F(V)

It is guaranteed that atomic numbers belongs to the given set:{1,2,3,4,..18,35,36,53,54,85,86}

It is guaranteed the two atomic numbers is either in the same period or in the same group

It is guaranteed that x≠y

Input

There are several test cases

For each test case,there are two numbers u,v,means
the atomic numbers of the two element

Output

For each test case,if F(u)>F(v),print
"FIRST BIGGER",else print"SECOND BIGGER"

Sample Input

1 2
5 3

Sample Output

SECOND BIGGER
FIRST BIGGER

Source

2015 Multi-University Training Contest 5

点击打开链接

#include <iostream>
#include <cstring>
#include <cstdio>
#include <stdlib.h>
#include <algorithm>
using namespace std;
int main()
{
    int a[25]=
    {
        2,10,9,18,7,36,8,
        1, 17, 54, 35, 6, 87,
        15,53,16,86,4,5,14,12,13,3,11
    };
    int x,y;
    while(~scanf("%d%d",&x,&y))
    {
        int xx,yy;
        for(int i=0; i<25; i++)
        {
            if(a[i]==x)
            {
                xx=i;
                break;
            }
        }

        for(int i=0; i<25; i++)
        {
            if(a[i]==y)
            {
                yy=i;
                break;
            }
        }
        if(xx<yy)
            printf("FIRST BIGGER\n");
        else printf("SECOND BIGGER\n");
    }
    return 0;
}

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HDU 5347 MZL's chemistry