题目大意:很多人@一个人,如果那个人忍不住说话了,就轰炸成功,如果那个人没说话或者别的人没有@他或@很多个人,则轰炸失败。(具体见原题)
解题思路:字符串处理,好好用sscanf即可(细节见代码)。
C++ Code:
#include<cstring> #include<algorithm> #include<cstdio> char s[1050],zha[1050],shuohua[1050],At[1050]; int q=1; int main(){ fgets(s,1005,stdin); sscanf(strstr(s,"@"),"@yyy loves %s",zha); while(1){ fgets(s,1005,stdin); if(strlen(s)<5)break;//读入结束 ++q; sscanf(s,"yyy loves %s",shuohua); if(strcmp(zha,shuohua)==0){//油炸成功 printf("Successful @yyy loves %s attempt\n",zha); return 0; } if(std::count(s,s+strlen(s),‘@‘)!=1){//队形被破坏,油炸失败 printf("Unsuccessful @yyy loves %s attempt\n%d\nyyy loves %s\n",zha,q,shuohua); return 0; }else{ sscanf(strstr(s,"@"),"@yyy loves %s",At); if(strcmp(At,zha)){//队形被破坏,油炸失败 printf("Unsuccessful @yyy loves %s attempt\n%d\nyyy loves %s\n",zha,q,shuohua); return 0; } } } //队形没有被打破 printf("Unsuccessful @yyy loves %s attempt\n%d\nGood Queue Shape\n",zha,q); return 0; }
时间: 2024-10-24 22:46:44