【Leetcode_easy】849. Maximize Distance to Closest Person

849. Maximize Distance to Closest Person 题目链接:https://leetcode.com/problems/maximize-distance-to-closest-person/description/ 思路:pre[i]存放i之前离最近的1的距离.post记录之后的. res = max(min(pre[i],[post[i])) 注意点:初始nst需要设计极大或极小值. 1 int maxDistToClosest(vector<int>&am

In a row of seats, 1 represents a person sitting in that seat, and 0 represents that the seat is empty. There is at least one empty seat, and at least one person sitting. Alex wants to sit in the seat such that the distance between him and the closes

1 class Solution 2 { 3 public: 4 int maxDistToClosest(vector<int>& seats) 5 { 6 int count=0; 7 int maxseat=0; 8 for(int i:seats) //count the max length of continuous 0 9 { 10 if(i==0) 11 count++; 12 else 13 { 14 maxseat=max(maxseat,count); 15 co

这是悦乐书的第328次更新,第351篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第198题(顺位题号是849).在一排座位中,1表示一个人坐在该座位上,0表示座位是空的.在这些座位中,至少有一个空座位,至少有一个人坐着.Alex想坐在座位上,以便他和离他最近的人之间的距离最远.返回距离最近的人的最大距离.例如: 输入:[1,0,0,0,1,0,1] 输出:2 说明:如果Alex坐在第二个空座位(seats[2]),那么离最近的人距离为2.如果Alex坐在任何其他空

因为a,b是同时出发,同时达到,但是他们的速度不一定一样,所以我们可以设他们的速度为La,Lb(La,Lb为a,b狗的总路程) 那么,如何a,b都是沿着直线运动的时候如何求他们之间的最短最长距离呢? 因为运动都是相对的,所以我们可以把a看成不懂的,而b相对于a的移动方向就是Vb - Va,因此就可以看成a和线段 b + (Vb -Va)之间的关系了 至于方向Va,Vb向量怎么求,我们可以利用单位向量 X 移动时间 X 移动速度 得到. 经典的一道题,顺便还修复了一个模板的BUG: 1412818

题目如下: You have a keyboard layout as shown above in the XY plane, where each English uppercase letter is located at some coordinate, for example, the letter A is located at coordinate (0,0), the letter B is located at coordinate (0,1), the letter P is

题目: Given two words word1 and word2, find the minimum number of steps required to convert word1 to word2. (each operation is counted as 1 step.) You have the following 3 operations permitted on a word: Insert a character Delete a character Replace a

problem 543. Diameter of Binary Tree 参考 1. Leetcode_easy_543. Diameter of Binary Tree; 完 原文地址:https://www.cnblogs.com/happyamyhope/p/10943221.html

problem 551. Student Attendance Record I 参考 1. Leetcode_easy_551. Student Attendance Record I; 完 原文地址:https://www.cnblogs.com/happyamyhope/p/10947954.html