大熊猫10分钟
这是对熊猫的简短介绍，主要面向新用户。您可以在Cookbook中看到更复杂的食谱。
通常，我们导入如下：
In [1]: import numpy as np In [2]: import pandas as pd
对象创建
请参阅数据结构简介部分。
创建一个Series通过传递值的列表，让大熊猫创建一个默认的整数索引：
In [3]: s = pd.Series([1, 3, 5, np.nan, 6, 8]) In [4]: s Out[4]: 0 1.0 1 3.0 2 5.0 3 NaN 4 6.0 5 8.0 dtype: float64
DataFrame通过传递带有日期时间索引和标记列的NumPy数组来创建：
In [5]: dates = pd.date_range(‘20130101‘, periods=6)
In [6]: dates
Out[6]:
DatetimeIndex([‘2013-01-01‘, ‘2013-01-02‘, ‘2013-01-03‘, ‘2013-01-04‘,
‘2013-01-05‘, ‘2013-01-06‘],
dtype=‘datetime64[ns]‘, freq=‘D‘)
In [7]: df = pd.DataFrame(np.random.randn(6, 4), index=dates, columns=list(‘ABCD‘))
In [8]: df
Out[8]:
A B C D
2013-01-01 0.469112 -0.282863 -1.509059 -1.135632
2013-01-02 1.212112 -0.173215 0.119209 -1.044236
2013-01-03 -0.861849 -2.104569 -0.494929 1.071804
2013-01-04 0.721555 -0.706771 -1.039575 0.271860
2013-01-05 -0.424972 0.567020 0.276232 -1.087401
2013-01-06 -0.673690 0.113648 -1.478427 0.524988
DataFrame通过传递可以转换为类似系列的对象的dict来创建。
In [9]: df2 = pd.DataFrame({‘A‘: 1.,
...: ‘B‘: pd.Timestamp(‘20130102‘),
...: ‘C‘: pd.Series(1, index=list(range(4)), dtype=‘float32‘),
...: ‘D‘: np.array([3] * 4, dtype=‘int32‘),
...: ‘E‘: pd.Categorical(["test", "train", "test", "train"]),
...: ‘F‘: ‘foo‘})
...:
In [10]: df2
Out[10]:
A B C D E F
0 1.0 2013-01-02 1.0 3 test foo
1 1.0 2013-01-02 1.0 3 train foo
2 1.0 2013-01-02 1.0 3 test foo
3 1.0 2013-01-02 1.0 3 train foo
结果的列DataFrame具有不同的 dtypes。
In [11]: df2.dtypes Out[11]: A float64 B datetime64[ns] C float32 D int32 E category F object dtype: object
如果您正在使用IPython，则会自动启用列名称（以及公共属性）的选项卡完成。以下是将要完成的属性的子集：
In [12]: df2.<TAB> # noqa: E225, E999 df2.A df2.bool df2.abs df2.boxplot df2.add df2.C df2.add_prefix df2.clip df2.add_suffix df2.clip_lower df2.align df2.clip_upper df2.all df2.columns df2.any df2.combine df2.append df2.combine_first df2.apply df2.compound df2.applymap df2.consolidate df2.D
正如你所看到的，列A，B，C，和D自动标签完成。E也有; 为简洁起见，其他属性已被截断。
查看数据
请参阅“ 基础”部分。
以下是查看框架的顶行和底行的方法：
In [13]: df.head()
Out[13]:
A B C D
2013-01-01 0.469112 -0.282863 -1.509059 -1.135632
2013-01-02 1.212112 -0.173215 0.119209 -1.044236
2013-01-03 -0.861849 -2.104569 -0.494929 1.071804
2013-01-04 0.721555 -0.706771 -1.039575 0.271860
2013-01-05 -0.424972 0.567020 0.276232 -1.087401
In [14]: df.tail(3)
Out[14]:
A B C D
2013-01-04 0.721555 -0.706771 -1.039575 0.271860
2013-01-05 -0.424972 0.567020 0.276232 -1.087401
2013-01-06 -0.673690 0.113648 -1.478427 0.524988
显示索引，列：
In [15]: df.index
Out[15]:
DatetimeIndex([‘2013-01-01‘, ‘2013-01-02‘, ‘2013-01-03‘, ‘2013-01-04‘,
‘2013-01-05‘, ‘2013-01-06‘],
dtype=‘datetime64[ns]‘, freq=‘D‘)
In [16]: df.columns
Out[16]: Index([‘A‘, ‘B‘, ‘C‘, ‘D‘], dtype=‘object‘)
DataFrame.to_numpy()给出基础数据的NumPy表示。请注意，当您DataFrame拥有不同数据类型的列时，他的操作可能很昂贵，这可归结为pandas和NumPy之间的根本差异：NumPy数组对整个数组有一个dtype，而pandas DataFrames每列有一个dtype。当你打电话时 DataFrame.to_numpy()，pandas会找到可以容纳 DataFrame中所有 dtypes 的NumPy dtype。这可能最终成为object，这需要将每个值都转换为Python对象。
因为df，我们DataFrame的所有浮点值 DataFrame.to_numpy()都很快，不需要复制数据。
In [17]: df.to_numpy()
Out[17]:
array([[ 0.4691, -0.2829, -1.5091, -1.1356],
[ 1.2121, -0.1732, 0.1192, -1.0442],
[-0.8618, -2.1046, -0.4949, 1.0718],
[ 0.7216, -0.7068, -1.0396, 0.2719],
[-0.425 , 0.567 , 0.2762, -1.0874],
[-0.6737, 0.1136, -1.4784, 0.525 ]])
因为df2，DataFrame具有多个dtypes， DataFrame.to_numpy()相对昂贵。
In [18]: df2.to_numpy()
Out[18]:
array([[1.0, Timestamp(‘2013-01-02 00:00:00‘), 1.0, 3, ‘test‘, ‘foo‘],
[1.0, Timestamp(‘2013-01-02 00:00:00‘), 1.0, 3, ‘train‘, ‘foo‘],
[1.0, Timestamp(‘2013-01-02 00:00:00‘), 1.0, 3, ‘test‘, ‘foo‘],
[1.0, Timestamp(‘2013-01-02 00:00:00‘), 1.0, 3, ‘train‘, ‘foo‘]], dtype=object)
注意
DataFrame.to_numpy()没有不包括在输出的索引或列标签。
describe() 显示数据的快速统计摘要：
In [19]: df.describe()
Out[19]:
A B C D
count 6.000000 6.000000 6.000000 6.000000
mean 0.073711 -0.431125 -0.687758 -0.233103
std 0.843157 0.922818 0.779887 0.973118
min -0.861849 -2.104569 -1.509059 -1.135632
25% -0.611510 -0.600794 -1.368714 -1.076610
50% 0.022070 -0.228039 -0.767252 -0.386188
75% 0.658444 0.041933 -0.034326 0.461706
max 1.212112 0.567020 0.276232 1.071804
转置您的数据：
In [20]: df.T Out[20]: 2013-01-01 2013-01-02 2013-01-03 2013-01-04 2013-01-05 2013-01-06 A 0.469112 1.212112 -0.861849 0.721555 -0.424972 -0.673690 B -0.282863 -0.173215 -2.104569 -0.706771 0.567020 0.113648 C -1.509059 0.119209 -0.494929 -1.039575 0.276232 -1.478427 D -1.135632 -1.044236 1.071804 0.271860 -1.087401 0.524988
按轴排序：
In [21]: df.sort_index(axis=1, ascending=False)
Out[21]:
D C B A
2013-01-01 -1.135632 -1.509059 -0.282863 0.469112
2013-01-02 -1.044236 0.119209 -0.173215 1.212112
2013-01-03 1.071804 -0.494929 -2.104569 -0.861849
2013-01-04 0.271860 -1.039575 -0.706771 0.721555
2013-01-05 -1.087401 0.276232 0.567020 -0.424972
2013-01-06 0.524988 -1.478427 0.113648 -0.673690
按值排序：
In [22]: df.sort_values(by=‘B‘)
Out[22]:
A B C D
2013-01-03 -0.861849 -2.104569 -0.494929 1.071804
2013-01-04 0.721555 -0.706771 -1.039575 0.271860
2013-01-01 0.469112 -0.282863 -1.509059 -1.135632
2013-01-02 1.212112 -0.173215 0.119209 -1.044236
2013-01-06 -0.673690 0.113648 -1.478427 0.524988
2013-01-05 -0.424972 0.567020 0.276232 -1.087401
选择
注意
虽然标准的Python / numpy的表达式选择和设置直观，派上用场的互动工作，为生产代码，我们建议优化的熊猫数据访问方法，.at，.iat， .loc和.iloc。
请参阅索引文档索引和选择数据以及MultiIndex / Advanced索引。
获得
选择一个列，产生一个Series，相当于df.A：
In [23]: df[‘A‘] Out[23]: 2013-01-01 0.469112 2013-01-02 1.212112 2013-01-03 -0.861849 2013-01-04 0.721555 2013-01-05 -0.424972 2013-01-06 -0.673690 Freq: D, Name: A, dtype: float64
选择via []，对行进行切片。
In [24]: df[0:3]
Out[24]:
A B C D
2013-01-01 0.469112 -0.282863 -1.509059 -1.135632
2013-01-02 1.212112 -0.173215 0.119209 -1.044236
2013-01-03 -0.861849 -2.104569 -0.494929 1.071804
In [25]: df[‘20130102‘:‘20130104‘]
Out[25]:
A B C D
2013-01-02 1.212112 -0.173215 0.119209 -1.044236
2013-01-03 -0.861849 -2.104569 -0.494929 1.071804
2013-01-04 0.721555 -0.706771 -1.039575 0.271860
按标签选择
在标签选择中查看更多信息。
使用标签获取横截面：
In [26]: df.loc[dates[0]] Out[26]: A 0.469112 B -0.282863 C -1.509059 D -1.135632 Name: 2013-01-01 00:00:00, dtype: float64
按标签选择多轴：
In [27]: df.loc[:, [‘A‘, ‘B‘]]
Out[27]:
A B
2013-01-01 0.469112 -0.282863
2013-01-02 1.212112 -0.173215
2013-01-03 -0.861849 -2.104569
2013-01-04 0.721555 -0.706771
2013-01-05 -0.424972 0.567020
2013-01-06 -0.673690 0.113648
显示标签切片，两个端点包括：
In [28]: df.loc[‘20130102‘:‘20130104‘, [‘A‘, ‘B‘]]
Out[28]:
A B
2013-01-02 1.212112 -0.173215
2013-01-03 -0.861849 -2.104569
2013-01-04 0.721555 -0.706771
减少返回对象的尺寸：
In [29]: df.loc[‘20130102‘, [‘A‘, ‘B‘]] Out[29]: A 1.212112 B -0.173215 Name: 2013-01-02 00:00:00, dtype: float64
获取标量值：
In [30]: df.loc[dates[0], ‘A‘] Out[30]: 0.46911229990718628
为了快速访问标量（相当于以前的方法）：
In [31]: df.at[dates[0], ‘A‘] Out[31]: 0.46911229990718628
按位置选择
在Position by Position中查看更多信息。
通过传递的整数的位置选择：
In [32]: df.iloc[3] Out[32]: A 0.721555 B -0.706771 C -1.039575 D 0.271860 Name: 2013-01-04 00:00:00, dtype: float64
通过整数切片，类似于numpy / python：
In [33]: df.iloc[3:5, 0:2]
Out[33]:
A B
2013-01-04 0.721555 -0.706771
2013-01-05 -0.424972 0.567020
通过整数位置位置列表，类似于numpy / python样式：
In [34]: df.iloc[[1, 2, 4], [0, 2]]
Out[34]:
A C
2013-01-02 1.212112 0.119209
2013-01-03 -0.861849 -0.494929
2013-01-05 -0.424972 0.276232
对于明确切片行：
In [35]: df.iloc[1:3, :]
Out[35]:
A B C D
2013-01-02 1.212112 -0.173215 0.119209 -1.044236
2013-01-03 -0.861849 -2.104569 -0.494929 1.071804
对于明确切片列：
In [36]: df.iloc[:, 1:3]
Out[36]:
B C
2013-01-01 -0.282863 -1.509059
2013-01-02 -0.173215 0.119209
2013-01-03 -2.104569 -0.494929
2013-01-04 -0.706771 -1.039575
2013-01-05 0.567020 0.276232
2013-01-06 0.113648 -1.478427
为了明确获取值：
In [37]: df.iloc[1, 1] Out[37]: -0.17321464905330858
为了快速访问标量（相当于以前的方法）：
In [38]: df.iat[1, 1] Out[38]: -0.17321464905330858
布尔索引
使用单个列的值来选择数据。
In [39]: df[df.A > 0]
Out[39]:
A B C D
2013-01-01 0.469112 -0.282863 -1.509059 -1.135632
2013-01-02 1.212112 -0.173215 0.119209 -1.044236
2013-01-04 0.721555 -0.706771 -1.039575 0.271860
从满足布尔条件的DataFrame中选择值。
In [40]: df[df > 0]
Out[40]:
A B C D
2013-01-01 0.469112 NaN NaN NaN
2013-01-02 1.212112 NaN 0.119209 NaN
2013-01-03 NaN NaN NaN 1.071804
2013-01-04 0.721555 NaN NaN 0.271860
2013-01-05 NaN 0.567020 0.276232 NaN
2013-01-06 NaN 0.113648 NaN 0.524988
使用isin()过滤方法：
In [41]: df2 = df.copy()
In [42]: df2[‘E‘] = [‘one‘, ‘one‘, ‘two‘, ‘three‘, ‘four‘, ‘three‘]
In [43]: df2
Out[43]:
A B C D E
2013-01-01 0.469112 -0.282863 -1.509059 -1.135632 one
2013-01-02 1.212112 -0.173215 0.119209 -1.044236 one
2013-01-03 -0.861849 -2.104569 -0.494929 1.071804 two
2013-01-04 0.721555 -0.706771 -1.039575 0.271860 three
2013-01-05 -0.424972 0.567020 0.276232 -1.087401 four
2013-01-06 -0.673690 0.113648 -1.478427 0.524988 three
In [44]: df2[df2[‘E‘].isin([‘two‘, ‘four‘])]
Out[44]:
A B C D E
2013-01-03 -0.861849 -2.104569 -0.494929 1.071804 two
2013-01-05 -0.424972 0.567020 0.276232 -1.087401 four
设定
设置新列会自动根据索引对齐数据。
In [45]: s1 = pd.Series([1, 2, 3, 4, 5, 6], index=pd.date_range(‘20130102‘, periods=6)) In [46]: s1 Out[46]: 2013-01-02 1 2013-01-03 2 2013-01-04 3 2013-01-05 4 2013-01-06 5 2013-01-07 6 Freq: D, dtype: int64 In [47]: df[‘F‘] = s1
按标签设置值：
In [48]: df.at[dates[0], ‘A‘] = 0
按位置设置值：
In [49]: df.iat[0, 1] = 0
通过使用NumPy数组进行设置：
In [50]: df.loc[:, ‘D‘] = np.array([5] * len(df))
先前设置操作的结果。
In [51]: df
Out[51]:
A B C D F
2013-01-01 0.000000 0.000000 -1.509059 5 NaN
2013-01-02 1.212112 -0.173215 0.119209 5 1.0
2013-01-03 -0.861849 -2.104569 -0.494929 5 2.0
2013-01-04 0.721555 -0.706771 -1.039575 5 3.0
2013-01-05 -0.424972 0.567020 0.276232 5 4.0
2013-01-06 -0.673690 0.113648 -1.478427 5 5.0
一个where与设置操作。
In [52]: df2 = df.copy()
In [53]: df2[df2 > 0] = -df2
In [54]: df2
Out[54]:
A B C D F
2013-01-01 0.000000 0.000000 -1.509059 -5 NaN
2013-01-02 -1.212112 -0.173215 -0.119209 -5 -1.0
2013-01-03 -0.861849 -2.104569 -0.494929 -5 -2.0
2013-01-04 -0.721555 -0.706771 -1.039575 -5 -3.0
2013-01-05 -0.424972 -0.567020 -0.276232 -5 -4.0
2013-01-06 -0.673690 -0.113648 -1.478427 -5 -5.0
缺少数据
pandas主要使用该值np.nan来表示缺失的数据。默认情况下，它不包含在计算中。请参阅缺失数据部分。
重建索引允许您更改/添加/删除指定轴上的索引。这将返回数据的副本。
In [55]: df1 = df.reindex(index=dates[0:4], columns=list(df.columns) + [‘E‘])
In [56]: df1.loc[dates[0]:dates[1], ‘E‘] = 1
In [57]: df1
Out[57]:
A B C D F E
2013-01-01 0.000000 0.000000 -1.509059 5 NaN 1.0
2013-01-02 1.212112 -0.173215 0.119209 5 1.0 1.0
2013-01-03 -0.861849 -2.104569 -0.494929 5 2.0 NaN
2013-01-04 0.721555 -0.706771 -1.039575 5 3.0 NaN
删除任何缺少数据的行。
In [58]: df1.dropna(how=‘any‘)
Out[58]:
A B C D F E
2013-01-02 1.212112 -0.173215 0.119209 5 1.0 1.0
填写缺失的数据。
In [59]: df1.fillna(value=5)
Out[59]:
A B C D F E
2013-01-01 0.000000 0.000000 -1.509059 5 5.0 1.0
2013-01-02 1.212112 -0.173215 0.119209 5 1.0 1.0
2013-01-03 -0.861849 -2.104569 -0.494929 5 2.0 5.0
2013-01-04 0.721555 -0.706771 -1.039575 5 3.0 5.0
获取值所在的布尔掩码nan。
In [60]: pd.isna(df1)
Out[60]:
A B C D F E
2013-01-01 False False False False True False
2013-01-02 False False False False False False
2013-01-03 False False False False False True
2013-01-04 False False False False False True
操作
统计
操作通常排除丢失的数据。
执行描述性统计：
In [61]: df.mean() Out[61]: A -0.004474 B -0.383981 C -0.687758 D 5.000000 F 3.000000 dtype: float64
另一个轴上的操作相同：
In [62]: df.mean(1) Out[62]: 2013-01-01 0.872735 2013-01-02 1.431621 2013-01-03 0.707731 2013-01-04 1.395042 2013-01-05 1.883656 2013-01-06 1.592306 Freq: D, dtype: float64
使用具有不同维度且需要对齐的对象进行操作。此外，pandas会自动沿指定维度进行广播。
In [63]: s = pd.Series([1, 3, 5, np.nan, 6, 8], index=dates).shift(2)
In [64]: s
Out[64]:
2013-01-01 NaN
2013-01-02 NaN
2013-01-03 1.0
2013-01-04 3.0
2013-01-05 5.0
2013-01-06 NaN
Freq: D, dtype: float64
In [65]: df.sub(s, axis=‘index‘)
Out[65]:
A B C D F
2013-01-01 NaN NaN NaN NaN NaN
2013-01-02 NaN NaN NaN NaN NaN
2013-01-03 -1.861849 -3.104569 -1.494929 4.0 1.0
2013-01-04 -2.278445 -3.706771 -4.039575 2.0 0.0
2013-01-05 -5.424972 -4.432980 -4.723768 0.0 -1.0
2013-01-06 NaN NaN NaN NaN NaN
申请
将函数应用于数据：
In [66]: df.apply(np.cumsum)
Out[66]:
A B C D F
2013-01-01 0.000000 0.000000 -1.509059 5 NaN
2013-01-02 1.212112 -0.173215 -1.389850 10 1.0
2013-01-03 0.350263 -2.277784 -1.884779 15 3.0
2013-01-04 1.071818 -2.984555 -2.924354 20 6.0
2013-01-05 0.646846 -2.417535 -2.648122 25 10.0
2013-01-06 -0.026844 -2.303886 -4.126549 30 15.0
In [67]: df.apply(lambda x: x.max() - x.min())
Out[67]:
A 2.073961
B 2.671590
C 1.785291
D 0.000000
F 4.000000
dtype: float64
直方图
在直方图和离散化中查看更多信息。
In [68]: s = pd.Series(np.random.randint(0, 7, size=10)) In [69]: s Out[69]: 0 4 1 2 2 1 3 2 4 6 5 4 6 4 7 6 8 4 9 4 dtype: int64 In [70]: s.value_counts() Out[70]: 4 5 6 2 2 2 1 1 dtype: int64
字符串方法
Series在str 属性中配备了一组字符串处理方法，可以轻松地对数组的每个元素进行操作，如下面的代码片段所示。请注意，str中的模式匹配通常默认使用正则表达式（在某些情况下总是使用它们）。在Vectorized String Methods中查看更多信息。
In [71]: s = pd.Series([‘A‘, ‘B‘, ‘C‘, ‘Aaba‘, ‘Baca‘, np.nan, ‘CABA‘, ‘dog‘, ‘cat‘]) In [72]: s.str.lower() Out[72]: 0 a 1 b 2 c 3 aaba 4 baca 5 NaN 6 caba 7 dog 8 cat dtype: object
合并
CONCAT
pandas提供了各种工具，可以轻松地将Series，DataFrame和Panel对象与各种设置逻辑组合在一起，用于索引和关联代数功能（在连接/合并类型操作的情况下）。
请参阅合并部分。
将pandas对象连接在一起concat()：
In [73]: df = pd.DataFrame(np.random.randn(10, 4))
In [74]: df
Out[74]:
0 1 2 3
0 -0.548702 1.467327 -1.015962 -0.483075
1 1.637550 -1.217659 -0.291519 -1.745505
2 -0.263952 0.991460 -0.919069 0.266046
3 -0.709661 1.669052 1.037882 -1.705775
4 -0.919854 -0.042379 1.247642 -0.009920
5 0.290213 0.495767 0.362949 1.548106
6 -1.131345 -0.089329 0.337863 -0.945867
7 -0.932132 1.956030 0.017587 -0.016692
8 -0.575247 0.254161 -1.143704 0.215897
9 1.193555 -0.077118 -0.408530 -0.862495
# break it into pieces
In [75]: pieces = [df[:3], df[3:7], df[7:]]
In [76]: pd.concat(pieces)
Out[76]:
0 1 2 3
0 -0.548702 1.467327 -1.015962 -0.483075
1 1.637550 -1.217659 -0.291519 -1.745505
2 -0.263952 0.991460 -0.919069 0.266046
3 -0.709661 1.669052 1.037882 -1.705775
4 -0.919854 -0.042379 1.247642 -0.009920
5 0.290213 0.495767 0.362949 1.548106
6 -1.131345 -0.089329 0.337863 -0.945867
7 -0.932132 1.956030 0.017587 -0.016692
8 -0.575247 0.254161 -1.143704 0.215897
9 1.193555 -0.077118 -0.408530 -0.862495
加入
SQL样式合并。请参阅数据库样式连接部分。
In [77]: left = pd.DataFrame({‘key‘: [‘foo‘, ‘foo‘], ‘lval‘: [1, 2]})
In [78]: right = pd.DataFrame({‘key‘: [‘foo‘, ‘foo‘], ‘rval‘: [4, 5]})
In [79]: left
Out[79]:
key lval
0 foo 1
1 foo 2
In [80]: right
Out[80]:
key rval
0 foo 4
1 foo 5
In [81]: pd.merge(left, right, on=‘key‘)
Out[81]:
key lval rval
0 foo 1 4
1 foo 1 5
2 foo 2 4
3 foo 2 5
另一个例子是：
In [82]: left = pd.DataFrame({‘key‘: [‘foo‘, ‘bar‘], ‘lval‘: [1, 2]})
In [83]: right = pd.DataFrame({‘key‘: [‘foo‘, ‘bar‘], ‘rval‘: [4, 5]})
In [84]: left
Out[84]:
key lval
0 foo 1
1 bar 2
In [85]: right
Out[85]:
key rval
0 foo 4
1 bar 5
In [86]: pd.merge(left, right, on=‘key‘)
Out[86]:
key lval rval
0 foo 1 4
1 bar 2 5
追加
将行附加到数据框。请参阅“ 附加” 部分。
In [87]: df = pd.DataFrame(np.random.randn(8, 4), columns=[‘A‘, ‘B‘, ‘C‘, ‘D‘])
In [88]: df
Out[88]:
A B C D
0 1.346061 1.511763 1.627081 -0.990582
1 -0.441652 1.211526 0.268520 0.024580
2 -1.577585 0.396823 -0.105381 -0.532532
3 1.453749 1.208843 -0.080952 -0.264610
4 -0.727965 -0.589346 0.339969 -0.693205
5 -0.339355 0.593616 0.884345 1.591431
6 0.141809 0.220390 0.435589 0.192451
7 -0.096701 0.803351 1.715071 -0.708758
In [89]: s = df.iloc[3]
In [90]: df.append(s, ignore_index=True)
Out[90]:
A B C D
0 1.346061 1.511763 1.627081 -0.990582
1 -0.441652 1.211526 0.268520 0.024580
2 -1.577585 0.396823 -0.105381 -0.532532
3 1.453749 1.208843 -0.080952 -0.264610
4 -0.727965 -0.589346 0.339969 -0.693205
5 -0.339355 0.593616 0.884345 1.591431
6 0.141809 0.220390 0.435589 0.192451
7 -0.096701 0.803351 1.715071 -0.708758
8 1.453749 1.208843 -0.080952 -0.264610
分组
通过“分组依据”，我们指的是涉及以下一个或多个步骤的过程：
- 根据某些标准将数据拆分为组
- 将功能独立应用于每个组
- 将结果组合成数据结构
请参阅分组部分。
In [91]: df = pd.DataFrame({‘A‘: [‘foo‘, ‘bar‘, ‘foo‘, ‘bar‘,
....: ‘foo‘, ‘bar‘, ‘foo‘, ‘foo‘],
....: ‘B‘: [‘one‘, ‘one‘, ‘two‘, ‘three‘,
....: ‘two‘, ‘two‘, ‘one‘, ‘three‘],
....: ‘C‘: np.random.randn(8),
....: ‘D‘: np.random.randn(8)})
....:
In [92]: df
Out[92]:
A B C D
0 foo one -1.202872 -0.055224
1 bar one -1.814470 2.395985
2 foo two 1.018601 1.552825
3 bar three -0.595447 0.166599
4 foo two 1.395433 0.047609
5 bar two -0.392670 -0.136473
6 foo one 0.007207 -0.561757
7 foo three 1.928123 -1.623033
分组然后将sum()函数应用于结果组。
In [93]: df.groupby(‘A‘).sum()
Out[93]:
C D
A
bar -2.802588 2.42611
foo 3.146492 -0.63958
按多列分组形成分层索引，我们再次可以应用该sum功能。
In [94]: df.groupby([‘A‘, ‘B‘]).sum()
Out[94]:
C D
A B
bar one -1.814470 2.395985
three -0.595447 0.166599
two -0.392670 -0.136473
foo one -1.195665 -0.616981
three 1.928123 -1.623033
two 2.414034 1.600434
重塑
堆栈
In [95]: tuples = list(zip(*[[‘bar‘, ‘bar‘, ‘baz‘, ‘baz‘,
....: ‘foo‘, ‘foo‘, ‘qux‘, ‘qux‘],
....: [‘one‘, ‘two‘, ‘one‘, ‘two‘,
....: ‘one‘, ‘two‘, ‘one‘, ‘two‘]]))
....:
In [96]: index = pd.MultiIndex.from_tuples(tuples, names=[‘first‘, ‘second‘])
In [97]: df = pd.DataFrame(np.random.randn(8, 2), index=index, columns=[‘A‘, ‘B‘])
In [98]: df2 = df[:4]
In [99]: df2
Out[99]:
A B
first second
bar one 0.029399 -0.542108
two 0.282696 -0.087302
baz one -1.575170 1.771208
two 0.816482 1.100230
该stack()方法“压缩”DataFrame列中的级别。
In [100]: stacked = df2.stack()
In [101]: stacked
Out[101]:
first second
bar one A 0.029399
B -0.542108
two A 0.282696
B -0.087302
baz one A -1.575170
B 1.771208
two A 0.816482
B 1.100230
dtype: float64
使用“堆叠”DataFrame或Series（具有MultiIndexas index），stack()is 的逆操作，unstack()默认情况下取消堆叠最后一级：
In [102]: stacked.unstack()
Out[102]:
A B
first second
bar one 0.029399 -0.542108
two 0.282696 -0.087302
baz one -1.575170 1.771208
two 0.816482 1.100230
In [103]: stacked.unstack(1)
Out[103]:
second one two
first
bar A 0.029399 0.282696
B -0.542108 -0.087302
baz A -1.575170 0.816482
B 1.771208 1.100230
In [104]: stacked.unstack(0)
Out[104]:
first bar baz
second
one A 0.029399 -1.575170
B -0.542108 1.771208
two A 0.282696 0.816482
B -0.087302 1.100230
数据透视表
请参阅数据透视表部分。
In [105]: df = pd.DataFrame({‘A‘: [‘one‘, ‘one‘, ‘two‘, ‘three‘] * 3,
.....: ‘B‘: [‘A‘, ‘B‘, ‘C‘] * 4,
.....: ‘C‘: [‘foo‘, ‘foo‘, ‘foo‘, ‘bar‘, ‘bar‘, ‘bar‘] * 2,
.....: ‘D‘: np.random.randn(12),
.....: ‘E‘: np.random.randn(12)})
.....:
In [106]: df
Out[106]:
A B C D E
0 one A foo 1.418757 -0.179666
1 one B foo -1.879024 1.291836
2 two C foo 0.536826 -0.009614
3 three A bar 1.006160 0.392149
4 one B bar -0.029716 0.264599
5 one C bar -1.146178 -0.057409
6 two A foo 0.100900 -1.425638
7 three B foo -1.035018 1.024098
8 one C foo 0.314665 -0.106062
9 one A bar -0.773723 1.824375
10 two B bar -1.170653 0.595974
11 three C bar 0.648740 1.167115
我们可以非常轻松地从这些数据生成数据透视表：
In [107]: pd.pivot_table(df, values=‘D‘, index=[‘A‘, ‘B‘], columns=[‘C‘])
Out[107]:
C bar foo
A B
one A -0.773723 1.418757
B -0.029716 -1.879024
C -1.146178 0.314665
three A 1.006160 NaN
B NaN -1.035018
C 0.648740 NaN
two A NaN 0.100900
B -1.170653 NaN
C NaN 0.536826
时间序列
pandas具有简单，强大且高效的功能，用于在频率转换期间执行重采样操作（例如，将第二数据转换为5分钟数据）。这在财务应用程序中非常常见，但不仅限于此。请参阅时间序列部分。
In [108]: rng = pd.date_range(‘1/1/2012‘, periods=100, freq=‘S‘) In [109]: ts = pd.Series(np.random.randint(0, 500, len(rng)), index=rng) In [110]: ts.resample(‘5Min‘).sum() Out[110]: 2012-01-01 25083 Freq: 5T, dtype: int64
时区代表：
In [111]: rng = pd.date_range(‘3/6/2012 00:00‘, periods=5, freq=‘D‘) In [112]: ts = pd.Series(np.random.randn(len(rng)), rng) In [113]: ts Out[113]: 2012-03-06 0.464000 2012-03-07 0.227371 2012-03-08 -0.496922 2012-03-09 0.306389 2012-03-10 -2.290613 Freq: D, dtype: float64 In [114]: ts_utc = ts.tz_localize(‘UTC‘) In [115]: ts_utc Out[115]: 2012-03-06 00:00:00+00:00 0.464000 2012-03-07 00:00:00+00:00 0.227371 2012-03-08 00:00:00+00:00 -0.496922 2012-03-09 00:00:00+00:00 0.306389 2012-03-10 00:00:00+00:00 -2.290613 Freq: D, dtype: float64
转换为另一个时区：
In [116]: ts_utc.tz_convert(‘US/Eastern‘) Out[116]: 2012-03-05 19:00:00-05:00 0.464000 2012-03-06 19:00:00-05:00 0.227371 2012-03-07 19:00:00-05:00 -0.496922 2012-03-08 19:00:00-05:00 0.306389 2012-03-09 19:00:00-05:00 -2.290613 Freq: D, dtype: float64
在时间跨度表示之间转换：
In [117]: rng = pd.date_range(‘1/1/2012‘, periods=5, freq=‘M‘) In [118]: ts = pd.Series(np.random.randn(len(rng)), index=rng) In [119]: ts Out[119]: 2012-01-31 -1.134623 2012-02-29 -1.561819 2012-03-31 -0.260838 2012-04-30 0.281957 2012-05-31 1.523962 Freq: M, dtype: float64 In [120]: ps = ts.to_period() In [121]: ps Out[121]: 2012-01 -1.134623 2012-02 -1.561819 2012-03 -0.260838 2012-04 0.281957 2012-05 1.523962 Freq: M, dtype: float64 In [122]: ps.to_timestamp() Out[122]: 2012-01-01 -1.134623 2012-02-01 -1.561819 2012-03-01 -0.260838 2012-04-01 0.281957 2012-05-01 1.523962 Freq: MS, dtype: float64
在句点和时间戳之间进行转换可以使用一些方便的算术函数。在下面的示例中，我们将季度频率与11月结束的年度转换为季度结束后的月末的上午9点：
In [123]: prng = pd.period_range(‘1990Q1‘, ‘2000Q4‘, freq=‘Q-NOV‘) In [124]: ts = pd.Series(np.random.randn(len(prng)), prng) In [125]: ts.index = (prng.asfreq(‘M‘, ‘e‘) + 1).asfreq(‘H‘, ‘s‘) + 9 In [126]: ts.head() Out[126]: 1990-03-01 09:00 -0.902937 1990-06-01 09:00 0.068159 1990-09-01 09:00 -0.057873 1990-12-01 09:00 -0.368204 1991-03-01 09:00 -1.144073 Freq: H, dtype: float64
分类
大熊猫可以在a中包含分类数据DataFrame。有关完整文档，请参阅 分类简介和API文档。
In [127]: df = pd.DataFrame({"id": [1, 2, 3, 4, 5, 6],
.....: "raw_grade": [‘a‘, ‘b‘, ‘b‘, ‘a‘, ‘a‘, ‘e‘]})
.....:
将原始成绩转换为分类数据类型。
In [128]: df["grade"] = df["raw_grade"].astype("category")
In [129]: df["grade"]
Out[129]:
0 a
1 b
2 b
3 a
4 a
5 e
Name: grade, dtype: category
Categories (3, object): [a, b, e]
将类别重命名为更有意义的名称（分配到 Series.cat.categories就位！）。
In [130]: df["grade"].cat.categories = ["very good", "good", "very bad"]
重新排序类别并同时添加缺少的类别（默认情况下返回新方法）。Series .catSeries
In [131]: df["grade"] = df["grade"].cat.set_categories(["very bad", "bad", "medium", .....: "good", "very good"]) .....: In [132]: df["grade"] Out[132]: 0 very good 1 good 2 good 3 very good 4 very good 5 very bad Name: grade, dtype: category Categories (5, object): [very bad, bad, medium, good, very good]
排序是按类别中的每个顺序排序，而不是词汇顺序。
In [133]: df.sort_values(by="grade") Out[133]: id raw_grade grade 5 6 e very bad 1 2 b good 2 3 b good 0 1 a very good 3 4 a very good 4 5 a very good
按分类列分组还显示空类别。
In [134]: df.groupby("grade").size()
Out[134]:
grade
very bad 1
bad 0
medium 0
good 2
very good 3
dtype: int64
绘图
请参阅绘图文档。
In [135]: ts = pd.Series(np.random.randn(1000), .....: index=pd.date_range(‘1/1/2000‘, periods=1000)) .....: In [136]: ts = ts.cumsum() In [137]: ts.plot() Out[137]: <matplotlib.axes._subplots.AxesSubplot at 0x7f7a2fc08240>
在DataFrame上，该plot()方法可以方便地使用标签绘制所有列：
In [138]: df = pd.DataFrame(np.random.randn(1000, 4), index=ts.index, .....: columns=[‘A‘, ‘B‘, ‘C‘, ‘D‘]) .....: In [139]: df = df.cumsum() In [140]: plt.figure() Out[140]: <Figure size 640x480 with 0 Axes> In [141]: df.plot() Out[141]: <matplotlib.axes._subplots.AxesSubplot at 0x7f7a2bf762b0> In [142]: plt.legend(loc=‘best‘) Out[142]: <matplotlib.legend.Legend at 0x7f7a2beac748>
获取数据进/出
CSV
In [143]: df.to_csv(‘foo.csv‘)
In [144]: pd.read_csv(‘foo.csv‘)
Out[144]:
Unnamed: 0 A B C D
0 2000-01-01 0.266457 -0.399641 -0.219582 1.186860
1 2000-01-02 -1.170732 -0.345873 1.653061 -0.282953
2 2000-01-03 -1.734933 0.530468 2.060811 -0.515536
3 2000-01-04 -1.555121 1.452620 0.239859 -1.156896
4 2000-01-05 0.578117 0.511371 0.103552 -2.428202
5 2000-01-06 0.478344 0.449933 -0.741620 -1.962409
6 2000-01-07 1.235339 -0.091757 -1.543861 -1.084753
.. ... ... ... ... ...
993 2002-09-20 -10.628548 -9.153563 -7.883146 28.313940
994 2002-09-21 -10.390377 -8.727491 -6.399645 30.914107
995 2002-09-22 -8.985362 -8.485624 -4.669462 31.367740
996 2002-09-23 -9.558560 -8.781216 -4.499815 30.518439
997 2002-09-24 -9.902058 -9.340490 -4.386639 30.105593
998 2002-09-25 -10.216020 -9.480682 -3.933802 29.758560
999 2002-09-26 -11.856774 -10.671012 -3.216025 29.369368
[1000 rows x 5 columns]
HDF5
读写HDFStores。
写入HDF5商店。
In [145]: df.to_hdf(‘foo.h5‘, ‘df‘)
从HDF5商店阅读。
In [146]: pd.read_hdf(‘foo.h5‘, ‘df‘)
Out[146]:
A B C D
2000-01-01 0.266457 -0.399641 -0.219582 1.186860
2000-01-02 -1.170732 -0.345873 1.653061 -0.282953
2000-01-03 -1.734933 0.530468 2.060811 -0.515536
2000-01-04 -1.555121 1.452620 0.239859 -1.156896
2000-01-05 0.578117 0.511371 0.103552 -2.428202
2000-01-06 0.478344 0.449933 -0.741620 -1.962409
2000-01-07 1.235339 -0.091757 -1.543861 -1.084753
... ... ... ... ...
2002-09-20 -10.628548 -9.153563 -7.883146 28.313940
2002-09-21 -10.390377 -8.727491 -6.399645 30.914107
2002-09-22 -8.985362 -8.485624 -4.669462 31.367740
2002-09-23 -9.558560 -8.781216 -4.499815 30.518439
2002-09-24 -9.902058 -9.340490 -4.386639 30.105593
2002-09-25 -10.216020 -9.480682 -3.933802 29.758560
2002-09-26 -11.856774 -10.671012 -3.216025 29.369368
[1000 rows x 4 columns]
Excel中
读写MS Excel。
写入excel文件。
In [147]: df.to_excel(‘foo.xlsx‘, sheet_name=‘Sheet1‘)
从excel文件中读取。
In [148]: pd.read_excel(‘foo.xlsx‘, ‘Sheet1‘, index_col=None, na_values=[‘NA‘])
Out[148]:
Unnamed: 0 A B C D
0 2000-01-01 0.266457 -0.399641 -0.219582 1.186860
1 2000-01-02 -1.170732 -0.345873 1.653061 -0.282953
2 2000-01-03 -1.734933 0.530468 2.060811 -0.515536
3 2000-01-04 -1.555121 1.452620 0.239859 -1.156896
4 2000-01-05 0.578117 0.511371 0.103552 -2.428202
5 2000-01-06 0.478344 0.449933 -0.741620 -1.962409
6 2000-01-07 1.235339 -0.091757 -1.543861 -1.084753
.. ... ... ... ... ...
993 2002-09-20 -10.628548 -9.153563 -7.883146 28.313940
994 2002-09-21 -10.390377 -8.727491 -6.399645 30.914107
995 2002-09-22 -8.985362 -8.485624 -4.669462 31.367740
996 2002-09-23 -9.558560 -8.781216 -4.499815 30.518439
997 2002-09-24 -9.902058 -9.340490 -4.386639 30.105593
998 2002-09-25 -10.216020 -9.480682 -3.933802 29.758560
999 2002-09-26 -11.856774 -10.671012 -3.216025 29.369368
[1000 rows x 5 columns]
陷阱
如果您尝试执行操作，您可能会看到如下异常：
>>> if pd.Series([False, True, False]):
... print("I was true")
Traceback
...
ValueError: The truth value of an array is ambiguous. Use a.empty, a.any() or a.all().
有关说明和操作，请参阅比较。
见陷阱也是如此。
原文地址：https://www.cnblogs.com/fpzs/p/10520857.html
时间： 2024-10-02 19:32:39