978. Basic Calculator
https://www.lintcode.com/problem/basic-calculator/description
public class Solution { /** * @param s: the given expression * @return: the result of expression */ public int calculate(String s) { // Write your code here Stack<Integer> stack = new Stack<Integer>(); int result =0; int number =0; int sign =1; for(int i =0;i<s.length();i++){ char c = s.charAt(i); if(Character.isDigit(c)){ number = 10*number + (int)(c-‘0‘); }else if(c==‘+‘){ result +=sign*number; number =0; sign =1; }else if(c == ‘-‘){ result += sign * number; number = 0; sign = -1; }else if(c == ‘(‘){ stack.push(result); stack.push(sign); sign = 1; result = 0; }else if(c == ‘)‘){ result += sign* number; number =0; result*=stack.pop(); result+=stack.pop(); } } if(number!=0){ result +=sign*number; } return result; } }
980. Basic Calculator II
https://www.lintcode.com/problem/basic-calculator-ii/description
public class Solution { /** * @param s: the given expression * @return: the result of expression */ public int calculate(String s) { // Write your code here if(s==null || s.length()==0){ return 0; } int len = s.length(); Stack<Integer> stack = new Stack<Integer>(); int num =0; char sign = ‘+‘; for(int i =0;i<len;i++){ if(Character.isDigit(s.charAt(i))){ num = num*10 + s.charAt(i)-‘0‘; } if((!Character.isDigit(s.charAt(i)) && ‘ ‘!=s.charAt(i)) ||i==len-1){ if(sign ==‘-‘){ stack.push(-num); } if(sign == ‘+‘){ stack.push(num); } if(sign == ‘*‘){ stack.push(stack.pop()*num); } if(sign == ‘/‘){ stack.push(stack.pop()/num); } sign = s.charAt(i); num =0; } } int re =0; for(int i:stack){ re +=i; } return re; } }
849. Basic Calculator III
https://www.lintcode.com/problem/basic-calculator-iii/description
public class Solution { /** * @param s: the expression string * @return: the answer */ public int calculate(String s) { // Write your code here if(s==null || s.length()==0){ return 0; } Stack<Integer> nums = new Stack<Integer>(); Stack<Character> opr = new Stack<Character>(); int num =0; for(int i=0;i<s.length();i++){ char c = s.charAt(i); if(c==‘ ‘){ continue; } if(Character.isDigit(c)){ num = c-‘0‘; while(i<s.length()-1 && Character.isDigit(s.charAt(i+1))){ num = num*10+ (s.charAt(i+1)-‘0‘); i++; } nums.push(num); num =0; }else if(c==‘(‘){ opr.push(c); }else if(c==‘)‘){ while(opr.peek()!=‘(‘){ nums.push(calculate(nums.pop(),nums.pop(),opr.pop())); } opr.pop(); }else if(c==‘+‘||c==‘-‘||c==‘*‘||c==‘/‘){ if(!opr.isEmpty()&&needCalFirst(opr.peek(),c)){ nums.push(calculate(nums.pop(),nums.pop(),opr.pop())); } opr.push(c); } } while(!opr.isEmpty()){ nums.push(calculate(nums.pop(),nums.pop(),opr.pop())); } return nums.pop(); } public int calculate(int num1, int num2, char op){ switch(op){ case ‘+‘:return num2+num1; case ‘-‘:return num2-num1; case ‘*‘:return num2*num1; case ‘/‘:return num2/num1; default:return 0; } } public boolean needCalFirst(char firstOp, char secondOp){ if(firstOp==‘(‘|| firstOp==‘)‘){ return false; } if((firstOp==‘+‘||firstOp==‘-‘)&&(secondOp==‘*‘||secondOp==‘/‘)){ return false; } return true; } }
368. Expression Evaluation
https://www.lintcode.com/problem/expression-evaluation/description?_from=ladder&&fromId=4
同849 只需注意输入可能不是一个可计算表达式 eg:{‘(‘,‘)‘}
public class Solution { /** * @param expression: a list of strings * @return: an integer */ public int evaluateExpression(String[] expression) { // write your code here if(expression==null || expression.length==0){ return 0; } String s = ""; for(int i=0;i<expression.length;i++){ s+=expression[i]; } Stack<Integer> nums = new Stack<Integer>(); Stack<Character> opr = new Stack<Character>(); int num =0; for(int i=0;i<s.length();i++){ char c = s.charAt(i); if(c==‘ ‘){ continue; } if(Character.isDigit(c)){ num = c-‘0‘; while(i<s.length()-1 && Character.isDigit(s.charAt(i+1))){ num = num*10+ (s.charAt(i+1)-‘0‘); i++; } nums.push(num); num =0; }else if(c==‘(‘){ opr.push(c); }else if(c==‘)‘){ while(opr.peek()!=‘(‘){ if(nums.size()>=2) nums.push(calculate(nums.pop(),nums.pop(),opr.pop())); } opr.pop(); }else if(c==‘+‘||c==‘-‘||c==‘*‘||c==‘/‘){ if(!opr.isEmpty()&&needCalFirst(opr.peek(),c)){ if(nums.size()>=2) nums.push(calculate(nums.pop(),nums.pop(),opr.pop())); } opr.push(c); } } while(!opr.isEmpty()){ if(nums.size()>=2) nums.push(calculate(nums.pop(),nums.pop(),opr.pop())); } if(nums.size()>0){ return nums.pop(); } return 0; } public int calculate(int num1, int num2, char op){ switch(op){ case ‘+‘:return num2+num1; case ‘-‘:return num2-num1; case ‘*‘:return num2*num1; case ‘/‘:return num2/num1; default:return 0; } } public boolean needCalFirst(char firstOp, char secondOp){ if(firstOp==‘(‘|| firstOp==‘)‘){ return false; } if((firstOp==‘+‘||firstOp==‘-‘)&&(secondOp==‘*‘||secondOp==‘/‘)){ return false; } return true; } }
原文地址:https://www.cnblogs.com/lizzyluvcoding/p/10772635.html
时间: 2024-11-04 19:41:36