一道类似高中数学竞赛的构造题目,我们应该是把a写成b的某种形式然后得出答案,唉~
思路来自http://www.voidcn.com/blog/u013614281/article/p-2701125.html~
a*a + ab = (a+t)*(a+t)
a*b = 2*a*t+t*t
a = t*t/(b-2t)
如果b是奇数,那么t = (b-1)/2
如果b是偶数,如果(b-2)/2是偶数,t = (b-2)/2
如果b是偶数,而且(b-2)/2是奇数,那么t = (b - 4)/2
代码如下:
#include <stdio.h> typedef long long ll; int main() { ll b; int t1; scanf("%d", &t1); while(t1--) { long long t; scanf("%lld", &b); if(b % 2 == 1) { t = (b - 1) / 2; printf("%lld\n", t * t); } else if(b % 2 == 0 && ( (b - 2) / 2) % 2 ==0) { t = (b - 2) / 2; printf("%lld\n", t * t / 2); } else { t = (b - 4) / 2; printf("%lld\n", t * t / 4); } } return 0; }
时间: 2024-10-17 10:53:14