A - Bridging Signals
Time Limit:2000MS Memory Limit:65536KB 64bit IO Format:%lld & %llu
Submit
Status
Practice
ZOJ 1986
Description
‘Oh no, they’ve done it again’, cries the chief designer at the Waferland chip factory. Once more the routing designers have screwed up completely, making the signals on the chip connecting the ports of two functional blocks cross each other all over the place. At this late stage of the process, it is too expensive to redo the routing. Instead, the engineers have to bridge the signals, using the third dimension, so that no two signals cross. However, bridging is a complicated operation, and thus it is desirable to bridge as few signals as possible. The call for a computer program that finds the maximum number of signals which may be connected on the silicon surface without crossing each other, is imminent. Bearing in mind that there may be thousands of signal ports at the boundary of a functional block, the problem asks quite a lot of the programmer. Are you up to the task?
Figure 1. To the left: The two blocks’ ports and their signal mapping (4, 2, 6, 3, 1, 5). To the right: At most three signals may be routed on the silicon surface without crossing each other. The dashed signals must be bridged.
A typical situation is schematically depicted in figure 1. The ports of the two functional blocks are numbered from 1 to p, from top to bottom. The signal mapping is described by a permutation of the numbers 1 to p in the form of a list of p unique numbers in the range 1 to p, in which the ith number specifies which port on the right side should be connected to the ith port on the left side. Two signals cross if and only if the straight lines connecting the two ports of each pair do.
Input
On the first line of the input, there is a single positive integer n, telling the number of test scenarios to follow. Each test scenario begins with a line containing a single positive integer p < 40000, the number of ports on the two functional blocks. Then follow p lines, describing the signal mapping:
On the ith line is the port number of the block on the right side which should be connected to the ith port of the block on the left side.
Output
For each test scenario, output one line containing the maximum number of signals which may be routed on the silicon surface without crossing each other.
Sample Input
4
6
4
2
6
3
1
5
10
2
3
4
5
6
7
8
9
10
1
8
8
7
6
5
4
3
2
1
9
5
8
9
2
3
1
7
4
6
Sample Output
3
9
1
4
n个测试样例。.
每个样例m个数
。。。。
求最长递增序列，，，直接dp ..（英语是硬伤）
#include<cstdio>
#include<cmath>
#include<cstring>
#include<iostream>
#include<algorithm>
#include<queue>
#include<vector>
#include<map>
#include<stack>
#pragma comment(linker,"/STACK:102400000,102400000")
#define pi acos(-1.0)
#define EPS 1e-6
#define INF (1<<24)
using namespace std;
int main()
{
int T;
// freopen("test.txt","r",stdin);
scanf("%d",&T);
while(T--)
{
int n;
int i,j;
int dp[40005];
int a[40005];
int flag[40005];
scanf("%d",&n);
for(i=0;i<n;i++) scanf("%d",&a[i]);
memset(dp,0,sizeof(dp));
for(i=0;i<n;i++) flag[i]=INF;
for(i=0;i<n;i++)
{
dp[i]=1;
while(a[i]>flag[dp[i]])
{
dp[i]++;
}
if(a[i]<flag[dp[i]]) flag[dp[i]]=a[i];
}
int ans=0;
for(i=0;i<n;i++) ans=max(ans,dp[i]);
printf("%d\n",ans);
}
return 0;
}版权声明：本文为博主原创文章，未经博主允许不得转载。