UVA_401:Palindromes

　AC：Time(29ms)     C++ 4.8.2

#include<stdio.h>
#include<string.h>
char * mirstr = "AAE3EHHIIJLJMM0OS2STTUUVVWWXXYYZ5Z88";
int dispose(char *);
int main(void)
{
    char str[25];
    int state;
    while(scanf("%s", str) == 1)
    {
        state = dispose(str);
        switch(state)
        {
            case 1: printf("%s -- is not a palindrome.\n\n", str); break;
            case 2: printf("%s -- is a regular palindrome.\n\n", str); break;
            case 3: printf("%s -- is a mirrored string.\n\n", str); break;
            case 4: printf("%s -- is a mirrored palindrome.\n\n", str); break;
        }
    }

    return 0;
}

int dispose(char * str)
{
    int i;
    bool palin = true;
    bool mirr = true;
    int len = strlen(str);
    int half_len = len / 2;
    // 判断回文
    for(i = 0; i < half_len; i++)
        if(str[i] != str[len-1-i])
            palin = false;

    char * p;
    // 判断镜像
    for(i = 0; i < len; i++)
    {
        p = strchr(mirstr, str[i]);
        if(!p)
        {
            mirr = false;
            break;
        }

        if(p[0] == ‘O‘ || p[0] == ‘0‘) // 字母O和数字0单独处理
        {    // 一开始这个花括号忘记了，导致最后一个测试数据失败，情况四变成了情况二，通过调试检查出了错误。
            if(str[len-1-i] != ‘O‘ && str[len-1-i] != ‘0‘)
            {
                mirr = false;
                break;
            }
        }
        else if(p[1] != str[len-1-i])
        {
            mirr = false;
            break;
        }
    }    

    if(palin == false && mirr == false)
        return 1;
    else if(palin == true && mirr == false)
        return 2;
    else if(palin == false && mirr == true)
        return 3;
    else
        return 4;

}