题目链接:uva 12326 &hdu
4092 Yummy Triangular Pizza
题目大意:给出n,表示用n个正三角形去组成图形,问可以组成多少种不同的三角形,旋转,镜像,都算同一种。
解题思路:参考别人的思路,很巧妙,主要就是建立三维坐标轴。
正立三角形x+y+z = 0
倒立三角形x+y+z ≠ 0
这样从初始装态为0 0 0的三角形开始逐个添加,每次进行旋转镜像,判断是否有没有重复。
每次判断重复的时候,枚举图形中的一个三角做为原点处理,生成hash值,以为n为多位16,所以x,y,z的范围不会大过8.
#include <cstdio>
#include <cstring>
#include <set>
#include <algorithm>
using namespace std;
const int maxn = 16;
struct Trian {
int x, y, z;
Trian () {};
Trian (int x, int y, int z) {
this->x = x;
this->y = y;
this->z = z;
}
Trian add (int type) {
int mv = (x+y+z == 0 ? 1 : -1);
if (type == 0)
return Trian(x, y+mv, z+mv);
else if (type == 1)
return Trian(x+mv, y, z+mv);
else
return Trian(x+mv, y+mv, z);
}
void rotate () {
int tmp = x;
x = y;
y = z;
z = tmp;
}
void overturn () {
x = 1 - x;
y = 1 - y;
z = -z;
}
void move (int x, int y, int z) {
this->x += x;
this->y += y;
this->z += z;
}
};
bool operator == (const Trian& a, const Trian& b) {
return a.x == b.x && a.y == b.y && a.z == b.z;
}
bool operator < (const Trian& a, const Trian& b) {
if (a.x != b.x)
return a.x < b.x;
else if (a.y != b.y)
return a.y < b.y;
else
return a.z < b.z;
}
struct Hash {
int cnt, key[maxn+5];
};
bool operator < (const Hash& a, const Hash& b) {
if (a.cnt != b.cnt)
return a.cnt < b.cnt;
for (int i = 0; i < a.cnt; i++)
if (a.key[i] != b.key[i])
return a.key[i] < b.key[i];
return false;
}
struct Pizz {
int cnt;
Trian arr[maxn+5];
Pizz () { cnt = 0; }
bool add (const Trian& u) {
for (int i = 0; i < cnt; i++)
if (arr[i] == u)
return false;
arr[cnt++] = u;
return true;
}
void remove () { cnt--; }
Hash getKey () {
Hash u;
u.cnt = cnt;
for (int i = 0; i < cnt; i++) {
u.key[i] = arr[i].x + 8;
u.key[i] <<= 4;
u.key[i] += arr[i].y + 8;
u.key[i] <<= 4;
u.key[i] += arr[i].z + 8;
}
return u;
}
};
set<Hash> vis;
int ans[maxn+5] = {0};
bool find (Pizz v) {
for (int i = 0; i < 3; i++) {
sort(v.arr, v.arr+v.cnt);
if (vis.find(v.getKey()) != vis.end())
return true;
for (int j = 0; j < v.cnt; j++)
v.arr[j].rotate();
}
return false;
}
bool search (Pizz u) {
for (int i = 0; i < u.cnt; i++) {
int x = u.arr[i].x;
int y = u.arr[i].y;
int z = u.arr[i].z;
Pizz v = u;
if (x + y + z == 0) {
for (int j = 0; j < v.cnt; j++)
v.arr[j].move(-x, -y, -z);
if (find(v))
return true;
} else {
for (int j = 0; j < v.cnt; j++) {
v.arr[j].overturn();
v.arr[j].move(x-1, y-1, z);
}
if (find(v))
return true;
}
}
return false;
}
void insert (Pizz u) {
for (int i = 0; i < 3; i++) {
sort(u.arr, u.arr+u.cnt);
vis.insert(u.getKey());
for (int j = 0; j < u.cnt; j++)
u.arr[j].rotate();
}
}
void dfs (Pizz u) {
if (u.cnt == maxn+1)
return;
if (search(u))
return;
insert(u);
ans[u.cnt]++;
for (int i = 0; i < u.cnt; i++) {
for (int j = 0; j < 3; j++) {
Trian v = u.arr[i].add(j);
if (u.add(v)) {
dfs(u);
u.remove();
}
}
}
}
int rec[maxn+5] = {0, 1, 1, 1, 4, 6, 19, 43, 120, 307, 866, 2336, 6588, 18373, 52119, 147700, 422016};
int main () {
/*
Pizz u;
u.add(Trian(0, 0, 0));
dfs(u);
for (int i = 0; i <= maxn; i++)
printf("%d\n", ans[i]);
*/
int cas, n;
scanf("%d", &cas);
for (int i = 1; i <= cas; i++) {
scanf("%d", &n);
printf("Case #%d: %d\n", i, rec[n]);
}
return 0;
}
uva 12326 & hdu 4092 - Yummy Triangular Pizza(哈希+打表)
时间: 2024-10-06 08:06:08