【HDOJ】1619 Unidirectional TSP

题目本身一点儿都不难,但是就是被字典序搞死了。写的挺麻烦,但是过了,逆向做好做一点儿。

  1 /* 1619 */
  2 #include <cstdio>
  3 #include <cstring>
  4 #include <cstdlib>
  5
  6 #define MAXN 15
  7 #define MAXM 105
  8 #define INF    9999999
  9
 10 int dp[MAXN][MAXM];
 11 int path[MAXN][MAXM];
 12 int map[MAXN][MAXM];
 13 int stack[MAXM], top;
 14 int d[3];
 15 int ans;
 16 int n, m;
 17
 18 void solve(int beg) {
 19     int i, j, k, tmp;
 20
 21     for (i=0; i<n; ++i)
 22         dp[i][m-1] = INF;
 23     dp[beg][m-1] = map[beg][m-1];
 24     path[beg][m-1] = -1;
 25
 26     for (j=m-2; j>=0; --j) {
 27         for (i=0; i<n; ++i) {
 28             if (i == 0)
 29                 d[0] = n - 1;
 30             else
 31                 d[0] = i - 1;
 32             d[1] = i;
 33             if (i == n-1)
 34                 d[2] = 0;
 35             else
 36                 d[2] = i + 1;
 37             if (dp[d[0]][j+1] == dp[d[1]][j+1]) {
 38                 k = d[0]<d[1] ? d[0]:d[1];
 39                 if (dp[k][j+1] == dp[d[2]][j+1])
 40                     k = k<d[2] ? k:d[2];
 41                 else if (dp[k][j+1] < dp[d[2]][j+1])
 42                     k = k;
 43                 else
 44                     k = d[2];
 45             } else if (dp[d[0]][j+1] < dp[d[1]][j+1]) {
 46                 if (dp[d[0]][j+1] == dp[d[2]][j+1])
 47                     k = d[0]<d[2] ? d[0]:d[2];
 48                 else if (dp[d[0]][j+1] < dp[d[2]][j+1])
 49                     k = d[0];
 50                 else
 51                     k = d[2];
 52             } else {
 53                 if (dp[d[1]][j+1] == dp[d[2]][j+1])
 54                     k = d[1]<d[2] ? d[1]:d[2];
 55                 else if (dp[d[1]][j+1] < dp[d[2]][j+1])
 56                     k = d[1];
 57                 else
 58                     k = d[2];
 59             }
 60             path[i][j] = k;
 61             dp[i][j] = dp[k][j+1];
 62             if (dp[i][j] != INF)
 63                 dp[i][j] += map[i][j];
 64         }
 65     }
 66
 67     tmp = INF;
 68     for (i=0; i<n; ++i) {
 69         if (dp[i][0] < tmp) {
 70             tmp = dp[i][0];
 71             k = i;
 72         }
 73     }
 74
 75     if (tmp < ans) {
 76         ans = tmp;
 77         top = 0;
 78         j = 0;
 79         stack[top++] = k + 1;
 80         while (path[k][j] >= 0) {
 81             stack[top++] = path[k][j] + 1;
 82             k = path[k][j];
 83             ++j;
 84         }
 85     }
 86 }
 87
 88 int main() {
 89     int i, j, k, tmp;
 90
 91     #ifndef ONLINE_JUDGE
 92         freopen("data.in", "r", stdin);
 93         freopen("data.out", "w", stdout);
 94     #endif
 95
 96     while (scanf("%d %d", &n, &m) != EOF) {
 97         for (i=0; i<n; ++i)
 98             for (j=0; j<m; ++j)
 99                 scanf("%d", &map[i][j]);
100         ans = INF;
101         for (i=0; i<n; ++i)
102             solve(i);
103
104         for (i=0; i<m-1; ++i)
105             printf("%d ", stack[i]);
106         printf("%d\n", stack[m-1]);
107         printf("%d\n", ans);
108     }
109
110     return 0;
111 }
时间: 2024-10-29 19:07:11

【HDOJ】1619 Unidirectional TSP的相关文章

【HDOJ】4956 Poor Hanamichi

基本数学题一道,看错位数,当成大数减做了,而且还把方向看反了.所求为最接近l的值. 1 #include <cstdio> 2 3 int f(__int64 x) { 4 int i, sum; 5 6 i = sum = 0; 7 while (x) { 8 if (i & 1) 9 sum -= x%10; 10 else 11 sum += x%10; 12 ++i; 13 x/=10; 14 } 15 return sum; 16 } 17 18 int main() { 1

【HDOJ】1099 Lottery

题意超难懂,实则一道概率论的题目.求P(n).P(n) = n*(1+1/2+1/3+1/4+...+1/n).结果如果可以除尽则表示为整数,否则表示为假分数. 1 #include <cstdio> 2 #include <cstring> 3 4 #define MAXN 25 5 6 __int64 buf[MAXN]; 7 8 __int64 gcd(__int64 a, __int64 b) { 9 if (b == 0) return a; 10 else return

【HDOJ】2844 Coins

完全背包. 1 #include <stdio.h> 2 #include <string.h> 3 4 int a[105], c[105]; 5 int n, m; 6 int dp[100005]; 7 8 int mymax(int a, int b) { 9 return a>b ? a:b; 10 } 11 12 void CompletePack(int c) { 13 int i; 14 15 for (i=c; i<=m; ++i) 16 dp[i]

【HDOJ】3509 Buge&#39;s Fibonacci Number Problem

快速矩阵幂,系数矩阵由多个二项分布组成.第1列是(0,(a+b)^k)第2列是(0,(a+b)^(k-1),0)第3列是(0,(a+b)^(k-2),0,0)以此类推. 1 /* 3509 */ 2 #include <iostream> 3 #include <string> 4 #include <map> 5 #include <queue> 6 #include <set> 7 #include <stack> 8 #incl

【HDOJ】1818 It&#39;s not a Bug, It&#39;s a Feature!

状态压缩+优先级bfs. 1 /* 1818 */ 2 #include <iostream> 3 #include <queue> 4 #include <cstdio> 5 #include <cstring> 6 #include <cstdlib> 7 #include <algorithm> 8 using namespace std; 9 10 #define MAXM 105 11 12 typedef struct {

【HDOJ】2424 Gary&#39;s Calculator

大数乘法加法,直接java A了. 1 import java.util.Scanner; 2 import java.math.BigInteger; 3 4 public class Main { 5 public static void main(String[] args) { 6 Scanner cin = new Scanner(System.in); 7 int n; 8 int i, j, k, tmp; 9 int top; 10 boolean flag; 11 int t

【HDOJ】2425 Hiking Trip

优先级队列+BFS. 1 #include <iostream> 2 #include <cstdio> 3 #include <cstring> 4 #include <queue> 5 using namespace std; 6 7 #define MAXN 25 8 9 typedef struct node_st { 10 int x, y, t; 11 node_st() {} 12 node_st(int xx, int yy, int tt)

【HDOJ】1686 Oulipo

kmp算法. 1 #include <cstdio> 2 #include <cstring> 3 4 char src[10005], des[1000005]; 5 int next[10005], total; 6 7 void kmp(char des[], char src[]){ 8 int ld = strlen(des); 9 int ls = strlen(src); 10 int i, j; 11 12 total = i = j = 0; 13 while (

【HDOJ】2795 Billboard

线段树.注意h范围(小于等于n). 1 #include <stdio.h> 2 #include <string.h> 3 4 #define MAXN 200005 5 #define lson l, mid, rt<<1 6 #define rson mid+1, r, rt<<1|1 7 #define mymax(x, y) (x>y) ? x:y 8 9 int nums[MAXN<<2]; 10 int h, w; 11 12