练习3-82

原文

Exercise 3.82. Redo exercise 3.5 on Monte Carlo integration in terms of streams. The stream version of estimate-integral will not have an argument telling how many trials to perform. Instead, it will produce a stream of estimates based on successively more trials.

代码

 (define (random-in-range low high)
         (let ((range (- high low)))
                 (+ low (* (random) range))))
 (define (random-number-pairs low1 high1 low2 high2)
         (cons-stream (cons (random-in-range low1 high1) (random-in-range low2 high2))
                                 (random-number-pairs low1 high1 low2 high2))) 

 (define (monte-carlo experiment-stream passed failed)
         (define (next passed failed)
                 (cons-stream (/ passed (+ passed failed))
                                          (monte-carlo (stream-cdr experiment-stream)
                                                                   passed
                                                                   failed)))
         (if (stream-car experiment-stream)
                 (next (+ passed 1) failed)
                 (next passed (+ failed 1)))) 

 (define (estimate-integral p x1 x2 y1 y2)
         (let ((area (* (- x2 x1) (- y2 y1)))
               (randoms (random-number-pairs x1 x2 y1 y2)))
                 (scale-stream (monte-carlo (stream-map p randoms) 0 0) area))) 

 (define (sum-of-square x y) (+ (* x x) (* y y)))
 (define f (lambda (x) (not (> (sum-of-square (- (car x) 1) (- (cdr x) 1)) 1))))
 (define pi-stream (estimate-integral f 0 2 0 2))