NO working today. Cause today is Thanks Giving Day

The employees of the R1 company often spend time together: they watch football, they go camping, they solve contests. So, it's no big deal that sometimes someone pays for someone else. Today is the day of giving out money rewards. The R1 company CEO

Could not find qmake configuration file default. 分析文件E:/QPlot/QPlot.pro时发生错误,放弃中. (Error while parsing file /*.pro. Giving up.) 还是Google给力,找到其他人的解决方法. I assume it will work as you expect if you go to "Tools" -> "Options-" -> &quo

2015: [Usaco2010 Feb]Chocolate Giving Time Limit: 10 Sec  Memory Limit: 162 MBSubmit: 269  Solved: 183[Submit][Status] Description Farmer John有B头奶牛(1<=B<=25000),有N(2*B<=N<=50000)个农场,编号1-N,有M(N-1<=M<=100000)条双向边,第i条边连接农场R_i和S_i(1<=R_i&

org.springframework.transaction.CannotCreateTransactionException: Could not open JDBC Connection for transaction; nested exception is java.sql.SQLException: Cannot create PoolableConnectionFactory (Could not create connection to database server. Atte

bzoj2015[Usaco2010 Feb]Chocolate Giving 题意: n点m边无向图,有k头奶牛要送礼,它必须去农场(1号节点)拿礼物然后到目的地送.问每只奶牛的最短距离.n≤50000 题解: 以1号节点为源点spfa求一次最短路即可(反正是无向边). 代码: 1 #include <cstdio> 2 #include <cstring> 3 #include <algorithm> 4 #include <queue> 5 #defi

裸最短路.. ------------------------------------------------------------------------------------ #include<cstdio> #include<cstring> #include<algorithm> #include<iostream> #include<queue> #define rep( i , n ) for( int i = 0 ; i <

就是按照一定顺序输出排序. 比如a欠b的钱就不能先输出a然后输出b. 本题的技巧就是,要求的是不能先输出a然后输出b,但是可以先输出b然后输出a. 故此可以按照a欠b的钱的关系,建立图,然后DFS深度优先搜索,然后逆向记录点,输出这些逆向点,也就是a欠b的钱,就先输出b然后输出a,那么这个顺序就满足要求了. 很狡猾的题意.要细心.不然就搞半天都白搞了. 题目连接:http://codeforces.com/problemset/problem/412/D #include <stdio.h>

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2015: [Usaco2010 Feb]Chocolate Giving Time Limit: 10 Sec  Memory Limit: 162 MBSubmit: 533  Solved: 348[Submit][Status][Discuss] Description Farmer John有B头奶牛(1<=B<=25000),有N(2*B<=N<=50000)个农场,编号1-N,有M(N-1<=M<=100000)条双向边,第i条边连接农场R_i和S_i(1

java.sql.SQLNonTransientConnectionException: Could not create connection to database server. Attempted reconnect 3 times. Giving up. at com.mysql.cj.jdbc.exceptions.SQLError.createSQLException(SQLError.java:108) ~[mysql-connector-java-8.0.11.jar:8.0.