Floyd+二叉树
#include<iostream>
#include<cstdlib>
#include<cstdio>
#include<cstring>
using namespace std;
int a[101];
int g[101][101];
int main()
{
int n,i,j,k,l,r,min,ans;
cin>>n;
for (i=1;i<=n;i++)
for (j=1;j<=n;j++)
g[i][j]=10000000;
for (i=1;i<=n;i++)
{
g[i][i]=0;
cin>>a[i]>>l>>r;
if (l>0) g[i][l]=g[l][i]=1;
if (r>0) g[i][r]=g[r][i]=1;
}
for (k=1;k<=n;k++)
for (i=1;i<=n;i++)
if (i!=k)
for (j=1;j<=n;j++)
if (i!=j&&k!=j&&g[i][k]+g[k][j]<g[i][j])
g[i][j]=g[i][k]+g[k][j];
min=0x7fffffff;
for (i=1;i<=n;i++)
{
ans=0;
for (j=1;j<=n;j++)
ans+=g[i][j]*a[j];
if (ans<min) min=ans;
}
cout<<min<<endl;
return 0;
}
时间: 2024-10-13 21:52:10