解题思路:
暴力绝对TLE
一个队伍穿主场球衣的次数 = 这个队伍的客场球衣颜色与其他队主场球衣颜色起冲突的次数 + (n - 1)
#include <stdio.h>
#include <string.h>
#include <iostream>
using namespace std;
const int MAXSIZE = 100;
const int INF = 0x3f3f3f3f;int a[100001], b[100001], c[100001], cnt[100001];
int main(){
int t, i, j, m, n;
memset(c, 0, sizeof(c));
memset(cnt, 0, sizeof(cnt));
scanf("%d",&n);
for(i = 1; i <= n; ++i){
scanf("%d%d",&a[i],&b[i]);
++cnt[a[i]];
}
for(i = 1; i <= n; ++i){
c[i] += n - 1;
c[i] += cnt[b[i]];
}
int temp = (n - 1) * 2;
for(i = 1; i <= n; ++i){
printf("%d %d\n",c[i],temp - c[i]);
}
return 0;
}
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时间: 2024-11-04 05:59:41