477. Total Hamming Distance 总的汉明距离

The Hamming distance between two integers is the number of positions at which the corresponding bits are different.

Now your job is to find the total Hamming distance between all pairs of the given numbers.

Example:

Input: 4, 14, 2

Output: 6

Explanation: In binary representation, the 4 is 0100, 14 is 1110, and 2 is 0010 (just
showing the four bits relevant in this case). So the answer will be:
HammingDistance(4, 14) + HammingDistance(4, 2) + HammingDistance(14, 2) = 2 + 2 + 2 = 6.

Note:

1. Elements of the given array are in the range of 0 to 10^9
2. Length of the array will not exceed 10^4.

class Solution1(object):
    def totalHammingDistance(self, nums):
        """
        :type nums: List[int]
        :rtype: int
        """
        res = 0
        bins = []
        for num in nums:
            bins.append(‘{0:b}‘.format(num).zfill(32))

        for i in range(32):
            bitCount = 0
            # zeroCount
            for num in bins:
                if num[i] is ‘1‘:
                    bitCount += 1
            # zeroCount = (len(nums) - bitCount)
            res += bitCount * (len(nums) - bitCount)
        return res


class Solution2(object):
    def totalHammingDistance(self, nums):
        res = 0
        for i in range(32):
            bitCount = 0
            for num in nums:
                bitCount += num >> i & 1
            res += bitCount * (len(nums) - bitCount)
        return res


nums = [4, 14, 2]
s = Solution1()
res = s.totalHammingDistance(nums)
print(res)

来自为知笔记(Wiz)

原文地址：https://www.cnblogs.com/xiejunzhao/p/8319176.html