dom4j如何解析xml

简单解析自己定义的xml文件，首先，给解析xml文件的类来个构造方法：

 1 public xmlData(File xmlFile)  {
 2         file = xmlFile;
 3         try {
 4             saxReader = new SAXReader();
 5             saxReader.setEncoding("UTF-8");
 6             doc = saxReader.read(this.file);
 7
 8             init();
 9         } catch (DocumentException e) {
10             throw new Exception("Open xml file " + xmlFile.getAbsolutePath()
11                 + " failed with error:" + e.getMessage());        }
12     }

下面是初始化数据的方法：

private void init() throws Exception {
        try {
            Node node = doc.selectSingleNode("//Com/User");
            user = node.valueOf("@User");
            name = node.valueOf("@Name");
           }catch(Exception e){
               throw new Exception("init xml file fail"+e.getMessage());
           }

   }