Codeforces 847E - Packmen

847E - Packmen

思路:二分时间。

代码:

#include<bits/stdc++.h>
using namespace std;
#define ll long long
#define pb push_back
#define mem(a,b) memset(a,b,sizeof(a))
int n;
string s;

bool check(int t)
{
    int now=-1,bean=-2;//now是上一个P覆盖到的位置,bean是没有被上一个P覆盖到的第一个星星
    for(int i=0;i<n;i++)
    {
        if(s[i]==‘*‘)
        {
            if(bean<=now)bean=i;
        }
        else if(s[i]==‘P‘)
        {
            if(now<bean)
            {
                if(i-bean>t)return false;
                else now=max((t-(i-bean))/2+i,bean+t-(i-bean));//P有两种走法,一种先往前再往后,另一种先往后再往前
            }
            else
            {
                now=i+t;
            }
        }
    }
    return now>=bean;
}

int binasrh(int l,int r)
{
    if(l==r)return l;
    int m=(l+r)>>1;
    if(check(m))binasrh(l,m);
    else binasrh(m+1,r);
}
int main()
{
    ios::sync_with_stdio(false);
    cin.tie(0);
    cin>>n>>s;
    cout<<binasrh(0,1000000)<<endl;
    return 0;
}
时间: 2024-10-04 18:19:27

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