先执行application的name对应的类呢还是activity中的name对应的类？

今天找程序入口发现了下面的情况有两个name我就写了个测试程序大致如下：

先看mainfest.xml

<application

android:allowBackup="true"

android:icon="@drawable/ic_launcher"

android:name="com.example.test1.app"

android:label="@string/app_name"

android:theme="@style/AppTheme" >

<activity

android:name="com.example.test1.MainActivity"

android:label="@string/app_name" >

<intent-filter>

<action android:name="android.intent.action.MAIN" />

<category android:name="android.intent.category.LAUNCHER" />

</intent-filter>

</activity>

</application>

k看app

package com.example.test1;

import android.app.Application;

import android.os.Bundle;

import android.util.Log;

public class app extends Application{

public void onCreate(){

super.onCreate();

Log.d("tt","application");

}

}

看activity如下

public class MainActivity extends Activity {

@Override

protected void onCreate(Bundle savedInstanceState) {

super.onCreate(savedInstanceState);

setContentView(R.layout.activity_main);

Log.d("tt","activity");

new app();

}

｝

最后我们来看日志文件就清楚了：

10-28 15:40:54.915: D/tt(4116): application

10-28 15:40:55.525: D/tt(4116): activity

这里就是说application 的name对应了类是在程序安装时候就创建了

然后我第二次打开如下：

只有一个信息

android.app.Application

Base class for those who need to maintain global application state. You can provide your own implementation by specifying its name in your AndroidManifest.xml‘s <application> tag, which will cause that class to be instantiated for you when the process for your
application/package is created.

Base class for those who need to maintain global application state. You can provide your own implementation by specifying its name in your AndroidManifest.xml‘s <application> tag, which will cause that class to be instantiated for you when the process for your
application/package is created.