HDU - 2199 ：Can you solve this equation? （二分）

Now,given the equation 8*x^4 + 7*x^3 + 2*x^2 + 3*x + 6 == Y,can you find its solution between 0 and 100;
Now please try your lucky.InputThe first line of the input contains an integer T(1<=T<=100) which means the number of test cases. Then T lines follow, each line has a real number Y (fabs(Y) <= 1e10);

OutputFor each test case, you should just output one real number(accurate up to 4 decimal places),which is the solution of the equation,or “No solution!”,if there is no solution for the equation between 0 and 100

Sample Input

2
100
-4

Sample Output

1.6152
No solution!

根据数学表达式用二分方法求近似解。

源代码：#include<iostream>#include<algorithm>#include <iomanip>

using namespace std;

int main()
{	int T,a;	cin>>T;	while(T--)	{		cin>>a;		a=a-6;		double low=0,hign=100,x,z;

if(a<0 || a>807020300)			cout<<"No solution!"<<endl;			else			{				while((hign-low)>1e-10)				{					x=(low+hign)/2;					z=8*x*x*x*x + 7*x*x*x+ 2*x*x + 3*x;					if(z>a)						hign=x;					if(z==a)						break;					if(z<a)						low=x;				}				cout<< setprecision(4)<<fixed<<x<<endl;			}

}

return 0;}